1.1 Two solid cylindrical rods AB and BC are welded together at B and loaded as shown. Knowing that d₁ = 30 mm and d₂ = 50 mm, find the average normal stress at the midsection of (a) rod AB, (b) rod BC. d₂ d₁ 125 kN B C 60 kN 125 kN 1.2 m 0.9 m

Q: A cylindrical rod AB has a length ? = 80 cm and a diameter of ? = 2 cm. The modulus of elasticity is…

A: Given Length of Rod, L=80cm Diameter of rod=2 cm Modulus of elasticity, E=200 GPa Force, P=100 kN…

Q: The couple M = 23 kN-m is applied to a beam of the cross sec angle with the vertical. Determine the…

A: Given : M = 23 KNm  and  β =150                           Find :  stress at A, B ,D = ?    Let the…

Q: 1. A solid shaft ABCD of diameter d is fixed at A and subjected to torques applied at equally spaced…

A: Since, we answer only three sub-parts at a time so we will answer the first three sub-parts. Please…

Q: 5 - An aluminum circular shaft, fixed at both ends, is loaded by torques applied at points B and C,…

A: Given Data  Shear modulus (G) = 85 GPa  Diameter of shaft (d) = 40mm  Length of AB (LAB) = 0.5m =…

Q: If the output torque on the CD shaft is T ́ = 75 N-m and the motor rotates at 175 rpm, determine the…

A: Given for CD shaft    diameter d2=35 mm, radius of gear R2=125 mmand torque T2=75 N-mfor EA shaft…

Q: 75 mm o T=3 kN.m 50 mm T=3 kN.m B Steel Bronze G-35 GN/m2 G=83 GN/m21

A:

Q: Two solid cylindrical rods AB and BC are welded together at B and loaded as shown. Take di = 30 mm,…

A: Determine the average normal stress at the midsection of rod BC.

Q: The solid 1.15-in.-diameter rod is subjected to a uniform axial distributed loading along its length…

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Q: Figure 40° 3 ksi B 5 ksi 1 of 1 Determine the stress components acting on the inclined plane AB in…

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Q: The following shaft consists of a 3.50 m long steel shaft and a 2.00 m long aluminum tube. The steel…

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Q: f the shaft?A

A: We knowμ=Lateral strainLongitudinal strainLateral strain=δddLongitudinal strain=δLL

Q: For the stress block shown, what is OP2 if OP1 = 140 MPa (T)? A.60 MPa (T) 40 MPa B.60 MPa (C) C.20…

A: Calculations:σx=+120mpaσy=-40Mpaσ1=140mpagivenσ1=σx+σy2+σx-σy2+ζxy2140=120-402+120+4022+ζxy2140=40+8…

Q: 1) The copper pipe below has an outer diameter of 50 mm, inner diameter of 30 mm, and G = 45 GPa. It…

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Q: What are appropriate relations established from the calculation of maximum shear stress in a thin…

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Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.