I'm stuck on this question:( 1.0cm 0.25mol dm potassium chromate(VI), K,Cro,, is added as an indicator.-3At the end-point, all the silver chloride has been precipitated in the 52.5 cm solution. A slightexcess of silver iois causes a red-brown precipitate of silver chromate(VI) to form.2Ag*(aq) + Cro,²-(aq) → Ag,CrO,(s)(1) The solubility product of silver chloride is:K = 2.0 x 10-10 mol? dm-6%3Dsp.Use this value to explain why [Ag*] = 1.41 x 10 mol dm 3 at the end-point.

At the end point all silver chloride is precipate out only that amount is present in the solution…

1.0cm 0.25 mol dm3 potassium chromate(VI), K,Cro,, is added as an indicator. At the end-point, all the silver chloride has been precipitated in the 52.5 cm solution. A slight excess of silver idis causes a red-brown precipitate of silver chromate(VI) to form. EAg*(aq) + Cro,2-(aq) → Ag,Cro̟(s) ) The solubility product of silver chloride is: K = 2.0 x 10-10 mol? dm 6 %3D Use this value to explain why [Ag*] = 1.41 x 10mol dm 3 at the end-point.

1.0cm 0.25 mol dm3 potassium chromate(VI), K,Cro,, is added as an indicator. At the end-point, all the silver chloride has been precipitated in the 52.5 cm solution. A slight excess of silver idis causes a red-brown precipitate of silver chromate(VI) to form. EAg(aq) + Cro,2-(aq) → Ag,Cro̟(s) ) The solubility product of silver chloride is: K = 2.0 x 10-10 mol? dm 6 %3D Use this value to explain why [Ag] = 1.41 x 10mol dm 3 at the end-point.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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