1. Which of the following can be solved by Law of cosines? 3 A. 4 C. 20° 40 5 5 3 110 B. 20⁰ D. 5 5 40⁰

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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1. Which of the following can be solved by Law of cosines?
3
A.
C.
20° 40
5
B.
D.
40°
5
5
2. Which of the following is true about the law of cosines?
A. The square of any side of a triangle is equal to the sum of the squares of the
other two sides minus the product of these sides and the cosine of their included
angle.
B. It is used to solve problems involving oblique triangles given two sides and an
excluded angle.
C. It is used to solve problems involving oblique triangles given three angles.
D. None of the above
3. Which of the following is best illustrates the problem?
A.
C.
15°
5 m
5 m
7m
7m
15°
5 m
B.
D.
7m
7m
4. Which of the following equation can be used to solve the problem? (Let d be the unknown)
A. d² = 5²+7²-2(5)(7) (cos 15)
B. 5²d²+7²-2(d)(7) (cos 15)
C. 7² 5²+d²-2(5)(d) (cos 15)
D. 15² = 5²+7²-2(5)(7) (cos d)
C. ≈ 1.77 m
D.. cannot be determined
15°
5
20⁰
15°
5. How far apart are the skaters?
A. ≈ 2.53m
B.. 1.96 m
110⁰
5m
Transcribed Image Text:1. Which of the following can be solved by Law of cosines? 3 A. C. 20° 40 5 B. D. 40° 5 5 2. Which of the following is true about the law of cosines? A. The square of any side of a triangle is equal to the sum of the squares of the other two sides minus the product of these sides and the cosine of their included angle. B. It is used to solve problems involving oblique triangles given two sides and an excluded angle. C. It is used to solve problems involving oblique triangles given three angles. D. None of the above 3. Which of the following is best illustrates the problem? A. C. 15° 5 m 5 m 7m 7m 15° 5 m B. D. 7m 7m 4. Which of the following equation can be used to solve the problem? (Let d be the unknown) A. d² = 5²+7²-2(5)(7) (cos 15) B. 5²d²+7²-2(d)(7) (cos 15) C. 7² 5²+d²-2(5)(d) (cos 15) D. 15² = 5²+7²-2(5)(7) (cos d) C. ≈ 1.77 m D.. cannot be determined 15° 5 20⁰ 15° 5. How far apart are the skaters? A. ≈ 2.53m B.. 1.96 m 110⁰ 5m
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