1. What vectors b are in the column space of A? Give constraint equations. (ch3.2.2a) A =| 6 -9
1. What vectors b are in the column space of A? Give constraint equations. (ch3.2.2a) A =| 6 -9
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![**Problem 1**: What vectors \( \mathbf{b} \) are in the column space of \( \mathbf{A} \)? Give constraint equations. (Reference: ch3.2.2a)
Matrix \( \mathbf{A} \) is given by:
\[
\mathbf{A} = \begin{bmatrix} 3 & -1 \\ 6 & -2 \\ -9 & 3 \end{bmatrix}
\]
To determine which vectors \( \mathbf{b} \) are in the column space of \( \mathbf{A} \), we must express \( \mathbf{b} \) as a linear combination of the columns of \( \mathbf{A} \). The column space of \( \mathbf{A} \) is the set of all vectors that can be written as:
\[
c_1 \begin{bmatrix} 3 \\ 6 \\ -9 \end{bmatrix} + c_2 \begin{bmatrix} -1 \\ -2 \\ 3 \end{bmatrix} = \begin{bmatrix} b_1 \\ b_2 \\ b_3 \end{bmatrix}
\]
Here, \( c_1 \) and \( c_2 \) are scalars, and \( \begin{bmatrix} b_1 \\ b_2 \\ b_3 \end{bmatrix} \) is the resulting vector \( \mathbf{b} \). Vectors \( \mathbf{b} \) in the column space must satisfy this form.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8541edea-69fb-4e9e-bec5-7b55484e2b45%2F02d5f772-d70d-4f4d-b540-a3be8c1fcc11%2Fonur5wn_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem 1**: What vectors \( \mathbf{b} \) are in the column space of \( \mathbf{A} \)? Give constraint equations. (Reference: ch3.2.2a)
Matrix \( \mathbf{A} \) is given by:
\[
\mathbf{A} = \begin{bmatrix} 3 & -1 \\ 6 & -2 \\ -9 & 3 \end{bmatrix}
\]
To determine which vectors \( \mathbf{b} \) are in the column space of \( \mathbf{A} \), we must express \( \mathbf{b} \) as a linear combination of the columns of \( \mathbf{A} \). The column space of \( \mathbf{A} \) is the set of all vectors that can be written as:
\[
c_1 \begin{bmatrix} 3 \\ 6 \\ -9 \end{bmatrix} + c_2 \begin{bmatrix} -1 \\ -2 \\ 3 \end{bmatrix} = \begin{bmatrix} b_1 \\ b_2 \\ b_3 \end{bmatrix}
\]
Here, \( c_1 \) and \( c_2 \) are scalars, and \( \begin{bmatrix} b_1 \\ b_2 \\ b_3 \end{bmatrix} \) is the resulting vector \( \mathbf{b} \). Vectors \( \mathbf{b} \) in the column space must satisfy this form.
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