1. What value of R will result in a balanced bridge? a) 300, b) 600Ω, c) 300Ω, d)3/ΟΚΩ 2. With R = 1000, what is the total resistance Rt? a) 1670, b) 463N, c) 4840, d) 456N 3. If R = 1.0k, what is the current through the 5000 resistor. Use the delta-wye conversion method. a) 455µA, b) 215μA, c) 4.55mA, d) 2.15mA 4. Using R 1.0k, what is the current throught the 5000 resistor. a) 2.15mA, b) 415µA, c) 455μµA, d) 215µA =

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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+
RT
10 V
200 Ω
600 Ω
500 Ω
Μ W
Μ
.100 Ω
R
Transcribed Image Text:+ RT 10 V 200 Ω 600 Ω 500 Ω Μ W Μ .100 Ω R
1. What value of R will result in a
balanced bridge? a) 300, b)
600Ω, c) 300Ω, d)3/ΟΚΩ
2. With R = 1000, what is the
total resistance Rt? a) 1670, b)
463N, c) 484N, d) 456N
3. If R = 1.0k, what is the
current through the 5000
resistor. Use the delta-wye
conversion method. a) 455µA,
b) 215µA, c) 4.55mA, d) 2.15mA
4. Using R 1.0k, what is the
current throught the 5000
resistor. a) 2.15mA, b) 415µA, c)
455µA, d) 215µA
=
Transcribed Image Text:1. What value of R will result in a balanced bridge? a) 300, b) 600Ω, c) 300Ω, d)3/ΟΚΩ 2. With R = 1000, what is the total resistance Rt? a) 1670, b) 463N, c) 484N, d) 456N 3. If R = 1.0k, what is the current through the 5000 resistor. Use the delta-wye conversion method. a) 455µA, b) 215µA, c) 4.55mA, d) 2.15mA 4. Using R 1.0k, what is the current throught the 5000 resistor. a) 2.15mA, b) 415µA, c) 455µA, d) 215µA =
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