1. What phase changes will take place when water is subjected to varying pressure at a constant temperature of a) 0.005 °C b) At 40 °C c) At –40 °C? Critical point 22,089 Water Ice (liquid) (solid) 101 Triple I point 0.6 Water vapor (gas) 0 0.01 100 374 Temperature (°C) Pressure (kPa)
1. What phase changes will take place when water is subjected to varying pressure at a constant temperature of a) 0.005 °C b) At 40 °C c) At –40 °C? Critical point 22,089 Water Ice (liquid) (solid) 101 Triple I point 0.6 Water vapor (gas) 0 0.01 100 374 Temperature (°C) Pressure (kPa)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![1. What phase changes will take place when water is subjected to varying pressure at a constant
temperature of a) 0.005 °C b) At 40 °C c) At –40 °C?
Critical point
22,089
Water
Ice
(liquid)
(solid)
101
Triple
I point
0.6
Water vapor
(gas)
0 0.01
100
374
Temperature (°C)
Pressure (kPa)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc2e8b864-3675-4e1b-a049-55ffe34aa1b7%2F03fd800d-d21c-4b0d-a67c-e39719cfb383%2Ffj13sza_processed.png&w=3840&q=75)
Transcribed Image Text:1. What phase changes will take place when water is subjected to varying pressure at a constant
temperature of a) 0.005 °C b) At 40 °C c) At –40 °C?
Critical point
22,089
Water
Ice
(liquid)
(solid)
101
Triple
I point
0.6
Water vapor
(gas)
0 0.01
100
374
Temperature (°C)
Pressure (kPa)
![Two components system containing liquid
The Gibbs phase rule
Consider a one component system composed of a liquid phases
with particular volume. Using the phase rule:
F = 1 -1+2= 2 (the
C = 2
P = 1 at least
F = C – P + 2
F = 3 (at most)
maximum number of
degree of freedom
for one component
system)
Only two independent
variables are required
to define the system
(temperature
pressure)
Three variables are required:
temperature,
composition
CRITICAL POINT
pressure
and
SOLID
LIQUID
If the pressure is fixed:
VAPOR
C = 2
F = C – P + 1
TRIPLE POINT
P = 1 at least
F = 2 (at most)
%3D
TEMPERATURE
and
Only
composition are required.
temperature
and
The Gibbs phase rule
The Gibbs phase rule is expressed as follows:
F = C – P + 2
where:
F is the number of degrees of freedom of the system which is
the least number of intensive variables required to define the
system completely.
C - number of components
P - number of phases present
PRESSURE](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc2e8b864-3675-4e1b-a049-55ffe34aa1b7%2F03fd800d-d21c-4b0d-a67c-e39719cfb383%2Ffi5st6d_processed.png&w=3840&q=75)
Transcribed Image Text:Two components system containing liquid
The Gibbs phase rule
Consider a one component system composed of a liquid phases
with particular volume. Using the phase rule:
F = 1 -1+2= 2 (the
C = 2
P = 1 at least
F = C – P + 2
F = 3 (at most)
maximum number of
degree of freedom
for one component
system)
Only two independent
variables are required
to define the system
(temperature
pressure)
Three variables are required:
temperature,
composition
CRITICAL POINT
pressure
and
SOLID
LIQUID
If the pressure is fixed:
VAPOR
C = 2
F = C – P + 1
TRIPLE POINT
P = 1 at least
F = 2 (at most)
%3D
TEMPERATURE
and
Only
composition are required.
temperature
and
The Gibbs phase rule
The Gibbs phase rule is expressed as follows:
F = C – P + 2
where:
F is the number of degrees of freedom of the system which is
the least number of intensive variables required to define the
system completely.
C - number of components
P - number of phases present
PRESSURE
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