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1. What is the relationship between the focal length of a cylindrical mirror and its radius of curvature Do your results confirm your answer? 2. What is the radius of curvature of a plane mirror

1. What is the relationship between the focal length of a cylindrical mirror and its radius of curvature Do your results confirm your answer? 2. What is the radius of curvature of a plane mirror

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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1. What is the relationship between the focal length of a cylindrical mirror and its radius of curvature Do your results confirm your answer?

2. What is the radius of curvature of a plane mirror?

Concave lense Focal length | :- 12.7 cm Radius of curvature = • n = 1.59 0 light rays 0 (°) MAS R₁ = + R • R₂ ==R focal length + = (1.59-1) (12/21 - 12/22 ) R₂ ((77-7) (650) = — = = (0.59) (²) R = (0.59) (2) +/1 24 = 2 (12,2)=24.4.600 18 12.7 - 14.986 cm * (1.18) of = 1.18*(-12.7) = 1.18 * (-12.7) = -14.986 cm
Transcribed Image Text:Concave lense Focal length | :- 12.7 cm Radius of curvature = • n = 1.59 0 light rays 0 (°) MAS R₁ = + R • R₂ ==R focal length + = (1.59-1) (12/21 - 12/22 ) R₂ ((77-7) (650) = — = = (0.59) (²) R = (0.59) (2) +/1 24 = 2 (12,2)=24.4.600 18 12.7 - 14.986 cm * (1.18) of = 1.18*(-12.7) = 1.18 * (-12.7) = -14.986 cm
Convex lense (converging. Focal length : +250 +13.8cm R====zf 1.59 o Radius of curvature à • Index of refraction n ¿ 0 light rays = -2 (12,5 cm) = +25,0cm R = +16.284cm focal length 13.8cm ++ +=(n-1) (1/2₁ - 1/₂ ) • R₂ = radius of curvature in front of surface. • R₁ = radius of curvature in back of surface. F R₁ = R₂ (same magnitude, diffent sign) (1.59 -1) ( 12/22 - (- 12)) + = t R = (0.59) (2) f = = 0.59 (2) R = 1.18 (13.8) = 16.284 cm SAAT IN
Transcribed Image Text:Convex lense (converging. Focal length : +250 +13.8cm R====zf 1.59 o Radius of curvature à • Index of refraction n ¿ 0 light rays = -2 (12,5 cm) = +25,0cm R = +16.284cm focal length 13.8cm ++ +=(n-1) (1/2₁ - 1/₂ ) • R₂ = radius of curvature in front of surface. • R₁ = radius of curvature in back of surface. F R₁ = R₂ (same magnitude, diffent sign) (1.59 -1) ( 12/22 - (- 12)) + = t R = (0.59) (2) f = = 0.59 (2) R = 1.18 (13.8) = 16.284 cm SAAT IN
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