1. What is the relationship between the focal length of a cylindrical mirror and its radius of curvature Do your results confirm your answer? 2. What is the radius of curvature of a plane mirror
1. What is the relationship between the focal length of a cylindrical mirror and its radius of curvature Do your results confirm your answer? 2. What is the radius of curvature of a plane mirror
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Applications Of Reflection Of Light
When a light ray (termed as the incident ray) hits a surface and bounces back (forms a reflected ray), the process of reflection of light has taken place.
Sign Convention for Mirrors
A mirror is made of glass that is coated with a metal amalgam on one side due to which the light ray incident on the surface undergoes reflection and not refraction.
Question
1. What is the relationship between the focal length of a cylindrical mirror and its radius of curvature Do your results confirm your answer?
2. What is the radius of curvature of a plane mirror?
Transcribed Image Text:Concave lense
Focal length | :- 12.7 cm
Radius of curvature =
• n = 1.59
0
light rays
0
(°)
MAS
R₁ = + R
• R₂ ==R
focal length
+ = (1.59-1) (12/21 - 12/22 )
R₂
((77-7) (650) = —
= = (0.59) (²)
R = (0.59) (2)
+/1
24 = 2 (12,2)=24.4.600
18
12.7
- 14.986 cm
* (1.18) of = 1.18*(-12.7)
=
1.18 * (-12.7) = -14.986 cm
Transcribed Image Text:Convex lense (converging.
Focal length : +250 +13.8cm
R====zf
1.59
o
Radius of curvature à
• Index of refraction n ¿
0
light rays
=
-2 (12,5 cm) = +25,0cm R = +16.284cm
focal length
13.8cm
++
+=(n-1) (1/2₁ - 1/₂ )
• R₂ = radius of curvature in front of surface.
• R₁ = radius of curvature in back of surface. F
R₁ = R₂ (same magnitude, diffent sign)
(1.59 -1) ( 12/22 - (- 12))
+ =
t
R = (0.59) (2) f
= = 0.59 (2)
R = 1.18 (13.8) = 16.284 cm
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