What is the focal length of a makeup mirror that produces a magnification of 1.5 when a person'sface is 12.2 cm away?Think & Prepare1. What kind of mirror causes magnification?2. What kind of image is it?3. What signs will the different quantities have?(a) Set-up the table for some known quantities.i) Make sure to use the correct sign for the image distances, object distances, and the focal lengths.ii) Make sure to use the correct sign for the image and object heights. Inverted object and imageheights are negative.iii) Do NOT do any calculations for this section.d₁ =M=(b) What is the focal length?f=cmcm

Step 1:a) Set up the table for the known quantitiesObject distance, do=-12.2 cmMagnification of the…

Answered: What is the focal length of a makeup…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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An object 1.7 cm high is held 3 cm from a person's cornea, and its reflected image is measured to be 0.157 cm high. Think & Prepare: 1. What kind of mirror is the cornea, convex or concave? 2. What kind of mirror causes magnification? 3. What kind of image is it? 4. What signs will the different quantities have? (a) Set-up the table for some known quantities. i) Make sure to use the correct sign for the image distances, object distances, and the focal lengths. ii) Make sure to use the correct sign for the image and object heights. Inverted object and image heights are negative. d₁ = = iii) Do NOT do any calculations for this section. h;= (b) What is the magnification? M= cm cm cm (Include the appropriate sign for an erect or inverted image) (c) Where is the image? d;= cm (include the appropriate sign) (d) Find the radius of curvature of the convex mirror formed by the cornea. cm (include the appropriate sign) R = Note that this technique is used by optometrists to measure the curvature…
Please help me with the following question and make sure your answer is correct, thanks 1. Please answer the following parts of the question Part A. An object is placed 11 cmcm in front of a spherical mirror. The image is half as tall as the object and inverted. Determine the focal length of the mirror. Express your answer with the appropriate units. Part B. An object is placed 70 cm in front of a thin lens. The image is four times as tall as the object and inverted. Determine the focal length of the lens. Express your answer with the appropriate units.
4. Diverging Lens - Object Inside Focal Point An object with heigh 0.75cm is placed a distance of 2.5 cm in front of a thin diverging lens with focal length -15cm. A. What is the image position in cm? Please draw a ray diagram and use the lens equation to solve algebraically. B. What is the image height? C. What is the magnification? ↑ 1 1 do d₁ + = 1 m= hi ho di do Skill: Find an Image Using 3 Principle Rays in Ray Diagram Skill: Find an Image Using the Lens Equation
B. CONVERGING LENSES: After performing this activity, the students should be able to: Sketch the location of the image in the concave mirror, measure the distance and the height of the image, and describe the object and the image in every case. MATERIALS: Rufer PROCEDURES 2 Construct the image of the following, given the focal length, distance of the object (do) (f) and height of the object (ho) in centimeters. Describe the location of both the object and the image being constructed. Determine the exact distance and the height of the image. identify the case number of each. Complete the table below. NOTE: Arrows that represent the secondary axes should be in red color, arrow that represent the object and the image is in blue color as well as the line that shows the bending of light ray, the rest of the construction is in black color. That is why you will be needing 3 colored ballpen for this activity. Use another sheet of bond paper for your construction. Use accurate maeasure. three…
A virtual upright image is .25 times the size of the object. a) If the object is 20.0 cm in front of the mirror what is the object distance. b) What is the focal length of the mirror and is it concave, convex, or plane? Show the algebraic form of any equation(s) applied. Report answers to with the correct units and number of significant figures.
A concave mirror produces a virtual image that is three times as tall as the object. Part A If the object is 12 cm in front of the mirror, what is the image distance? Express your answer using two significant figures. ΑΣφ ? di = cm Submit Request Answer Part B What is the focal length of this mirror? Express your answer using two significant figures. nν ΑΣφ ? cm Submit Request Answer

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