1. What is the probability that 5 is greater than in a normally distributed data given that the mean is 6, and the standard deviation is 0.7. Solution P(X < 5) the first step is to find the z- score. We find that using the formula above.
1. What is the probability that 5 is greater than in a normally distributed data given that the mean is 6, and the standard deviation is 0.7. Solution P(X < 5) the first step is to find the z- score. We find that using the formula above.
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Question
![01:16
O Interactive Mathematics
Solution
1. What is the probability that 5 is greater than x
in a normally distributed data given that the
mean is 6, and the standard deviation is 0.7.
M
= 0.07636
P(X < 5) the first step is to find the z- score. We
find that using the formula above.
-
z = (x − µ (mean)) / o (standard deviation) this
means that
For P(X<5), z = (5-6)/0.7
-1/7 = -1.42857 which is rounded up to - 1.43
Now in the table, we will look for the value of
-1.4 under 3
Ad
7.00
KB/S
The normal return for the z-score is usually less
than, and because the function is asking for the
probability of x being less than 5, this will be our
final answer.
s
61
2. What is the probability that x is greater than
4.5 in a normally distributed data given that the
mean is 6, and the standard deviation is 0.7.
1
DEVICE
1
DEVICE
McAfee
DX](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F604c1a3e-0cad-4dbb-9f89-b766777041eb%2Fd98635f3-d9c1-4211-837d-8981c41dd853%2Fea3v0be_processed.jpeg&w=3840&q=75)
Transcribed Image Text:01:16
O Interactive Mathematics
Solution
1. What is the probability that 5 is greater than x
in a normally distributed data given that the
mean is 6, and the standard deviation is 0.7.
M
= 0.07636
P(X < 5) the first step is to find the z- score. We
find that using the formula above.
-
z = (x − µ (mean)) / o (standard deviation) this
means that
For P(X<5), z = (5-6)/0.7
-1/7 = -1.42857 which is rounded up to - 1.43
Now in the table, we will look for the value of
-1.4 under 3
Ad
7.00
KB/S
The normal return for the z-score is usually less
than, and because the function is asking for the
probability of x being less than 5, this will be our
final answer.
s
61
2. What is the probability that x is greater than
4.5 in a normally distributed data given that the
mean is 6, and the standard deviation is 0.7.
1
DEVICE
1
DEVICE
McAfee
DX
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