1. What is a limiting reactant? Excess reactant?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
Question
### Chemistry: Understanding Reactants, Mass, and Yield

1. **What is a limiting reactant? Excess reactant?**
   - In a chemical reaction, a limiting reactant is the substance that is totally consumed first and limits the extent of the reaction, determining the amount of product formed. An excess reactant is the substance that is present in a quantity greater than necessary to react with the limiting reactant, meaning there is some left over after the reaction is complete.

2. **Why do we use the “constant mass” of NaCl in the experiment, and not the average mass?**
   - Using the "constant mass" of NaCl ensures accuracy and precision. It involves heating the sample to remove all moisture and allows it to cool in a desiccator, repeating the process until the mass remains constant. This eliminates errors due to moisture absorption, providing a more accurate measurement than using an average mass, which can vary due to external factors.

3. **What is the name of the chemical product at the end of both reactions? Is the mass of the chemical product you measure considered the actual yield or the theoretical yield?**
   - The name of the chemical product will depend on the specific reactions being conducted. The mass measured in an experiment usually represents the actual yield, which is the amount of product obtained. This can differ from the theoretical yield, which is the calculated maximum amount of product that could be formed from the given quantities of reactants.

4. **What is the percent yield of a reaction that produces 10.5 g CF₂Cl₂ from 29.9 g of CCl₄ and excess HF?**
   - The reaction is as follows: 
     \[
     \text{CCl}_4(\text{l}) + 2 \text{HF}(\text{aq}) \rightarrow \text{CF}_2\text{Cl}_2(\text{g}) + 2 \text{HCl}(\text{aq})
     \]
   - To find the percent yield, first calculate the theoretical yield of CF₂Cl₂ based on the limiting reactant, CCl₄. Then, use the formula:
     \[
     \text{Percent Yield} = \left(\frac{\text{Actual Yield}}{\text{Theoretical Yield}}\right) \times 100\%
     \]
   - (Calculations would require additional data such as molar masses).
Transcribed Image Text:### Chemistry: Understanding Reactants, Mass, and Yield 1. **What is a limiting reactant? Excess reactant?** - In a chemical reaction, a limiting reactant is the substance that is totally consumed first and limits the extent of the reaction, determining the amount of product formed. An excess reactant is the substance that is present in a quantity greater than necessary to react with the limiting reactant, meaning there is some left over after the reaction is complete. 2. **Why do we use the “constant mass” of NaCl in the experiment, and not the average mass?** - Using the "constant mass" of NaCl ensures accuracy and precision. It involves heating the sample to remove all moisture and allows it to cool in a desiccator, repeating the process until the mass remains constant. This eliminates errors due to moisture absorption, providing a more accurate measurement than using an average mass, which can vary due to external factors. 3. **What is the name of the chemical product at the end of both reactions? Is the mass of the chemical product you measure considered the actual yield or the theoretical yield?** - The name of the chemical product will depend on the specific reactions being conducted. The mass measured in an experiment usually represents the actual yield, which is the amount of product obtained. This can differ from the theoretical yield, which is the calculated maximum amount of product that could be formed from the given quantities of reactants. 4. **What is the percent yield of a reaction that produces 10.5 g CF₂Cl₂ from 29.9 g of CCl₄ and excess HF?** - The reaction is as follows: \[ \text{CCl}_4(\text{l}) + 2 \text{HF}(\text{aq}) \rightarrow \text{CF}_2\text{Cl}_2(\text{g}) + 2 \text{HCl}(\text{aq}) \] - To find the percent yield, first calculate the theoretical yield of CF₂Cl₂ based on the limiting reactant, CCl₄. Then, use the formula: \[ \text{Percent Yield} = \left(\frac{\text{Actual Yield}}{\text{Theoretical Yield}}\right) \times 100\% \] - (Calculations would require additional data such as molar masses).
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Similar questions
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY