1. What can you say about current and voltage in a series circuit. Explain the differences. Draw a circuit with 2 resistors in series and clearly explain. 2. What can you say about current and voltage in a parallel circuit. Explain the differences. Draw a circuit with 2 resistors in parallel and clearly explain.
1. What can you say about current and voltage in a series circuit. Explain the differences. Draw a circuit with 2 resistors in series and clearly explain. 2. What can you say about current and voltage in a parallel circuit. Explain the differences. Draw a circuit with 2 resistors in parallel and clearly explain.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Hello, based on the information in the pictures. Can you please help me solve the last two questions
![**Data Table I: One Resistor**
- **Color Code:** Yellow, Orange, Yellow, Gold
- **\( R_1 = 430,000 \, \Omega, \, 5\% \)**
| Measured Voltage [V] | Measured Current [A] | Calculated Resistance* [Ω] | Resistance Value from Color Code [Ω] |
|----------------------|----------------------|---------------------------|--------------------------------------|
| 2.92 V | 1.62 A | 1.8 Ω | 430,000 |
\( R = \frac{2.92}{1.62} = 1.8 \, \Omega \)
1. **Use Ohm's Law**: \( R = V/I \) to calculate resistance after you measured voltage and current.
\[
R_2 = \frac{2.92}{1.62} = 1.8 \, \Omega
\]
2. **Determine your % error** between the value of the resistor given by the color code (consider as standard value) and your calculated value (from 1).
\[
\left(\frac{1.8 - 430000}{430000}\right) \times 100 = -99\%
\]
---
**Data Table II: Resistors in Series**
- Record the color code for the 2 resistors used:
- **Color Code:** Yellow, Orange, Yellow, Gold
- \( R_1 = 430,000 \, \Omega, \, 5\% \)
- **Color Code:** Brown, Black, Red, Gold
- \( R_2 = 1000 \, \Omega, \, 5\% \)
| Measured Voltage [V] | Measured Current [A] | Resistance [Ω] calculated using Ohm's Law | Resistance Value from Color Code [Ω] |
|----------------------|----------------------|------------------------------------------|--------------------------------------|
| \( V_1 = 2.79 \, V \) | \( I_1 = 2.80 \, A \) | \( R_1 = 0.99 \, \Omega \) | \( R_1 = 430000 \, \Omega \) |
| \( V_2 = 2.81 \, V \) |](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F549651ba-b33d-474d-abf4-48863f7a8bc4%2F17d31a30-74a3-4d95-b4bf-e747abb60544%2Fztu9wjh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Data Table I: One Resistor**
- **Color Code:** Yellow, Orange, Yellow, Gold
- **\( R_1 = 430,000 \, \Omega, \, 5\% \)**
| Measured Voltage [V] | Measured Current [A] | Calculated Resistance* [Ω] | Resistance Value from Color Code [Ω] |
|----------------------|----------------------|---------------------------|--------------------------------------|
| 2.92 V | 1.62 A | 1.8 Ω | 430,000 |
\( R = \frac{2.92}{1.62} = 1.8 \, \Omega \)
1. **Use Ohm's Law**: \( R = V/I \) to calculate resistance after you measured voltage and current.
\[
R_2 = \frac{2.92}{1.62} = 1.8 \, \Omega
\]
2. **Determine your % error** between the value of the resistor given by the color code (consider as standard value) and your calculated value (from 1).
\[
\left(\frac{1.8 - 430000}{430000}\right) \times 100 = -99\%
\]
---
**Data Table II: Resistors in Series**
- Record the color code for the 2 resistors used:
- **Color Code:** Yellow, Orange, Yellow, Gold
- \( R_1 = 430,000 \, \Omega, \, 5\% \)
- **Color Code:** Brown, Black, Red, Gold
- \( R_2 = 1000 \, \Omega, \, 5\% \)
| Measured Voltage [V] | Measured Current [A] | Resistance [Ω] calculated using Ohm's Law | Resistance Value from Color Code [Ω] |
|----------------------|----------------------|------------------------------------------|--------------------------------------|
| \( V_1 = 2.79 \, V \) | \( I_1 = 2.80 \, A \) | \( R_1 = 0.99 \, \Omega \) | \( R_1 = 430000 \, \Omega \) |
| \( V_2 = 2.81 \, V \) |
![# Data Table III: Resistors in Parallel
Record the color code for the 2 resistors used:
| Measured Voltage [V] | Measured Current [A] | Calculated Resistance* [Ω] | Resistance Value from Color Code [Ω] |
|----------------------|----------------------|----------------------------|-------------------------------------|
| \( V_1 = 2.79 \) | \( I_1 = 2.05 A \) | \( R_1 = 1.36 \, Ω \) | \( R_1 = 430,000 \, Ω \) |
| \( V_2 = 2.8 \) | \( I_2 = 2.12 A \) | \( R_2 = 1.32 \, Ω \) | \( R_2 = 1,000 \, Ω \) |
| \( V_{total} = 5.59 \) | \( I_{total} = 4.17 A \) | \( R_{total} = 2.68 \, Ω \) | \( R_c \, (calculated \, at \, 5\%) = 431,000 \, Ω \) |
**Use Ohm’s Law: \( R = V/I \)**
- **Calculate the Resistances Using Ohm’s Law:**
- \( R_1 = \frac{V_1}{I_1} = \frac{2.79}{2.05} = 1.36 \, Ω \)
- \( R_2 = \frac{V_2}{I_2} = \frac{2.8}{2.12} = 1.32 \, Ω \)
- **Calculate the Equivalent Resistance Using the Parallel Resistance Formula:**
\[
\frac{1}{R_e} = \frac{1}{R_1} + \frac{1}{R_2}
\]
Consider the values of resistance provided by the color code.
\[
R_e = \frac{430,000 \cdot 1,000}{430,000 + 1,000} = \text{calculated value}
\]
- **Determine Your % Error Between the Two Values Found for the Total Resistance:**
\[
\text{Error} = \left( \](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F549651ba-b33d-474d-abf4-48863f7a8bc4%2F17d31a30-74a3-4d95-b4bf-e747abb60544%2F4jpsyoc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:# Data Table III: Resistors in Parallel
Record the color code for the 2 resistors used:
| Measured Voltage [V] | Measured Current [A] | Calculated Resistance* [Ω] | Resistance Value from Color Code [Ω] |
|----------------------|----------------------|----------------------------|-------------------------------------|
| \( V_1 = 2.79 \) | \( I_1 = 2.05 A \) | \( R_1 = 1.36 \, Ω \) | \( R_1 = 430,000 \, Ω \) |
| \( V_2 = 2.8 \) | \( I_2 = 2.12 A \) | \( R_2 = 1.32 \, Ω \) | \( R_2 = 1,000 \, Ω \) |
| \( V_{total} = 5.59 \) | \( I_{total} = 4.17 A \) | \( R_{total} = 2.68 \, Ω \) | \( R_c \, (calculated \, at \, 5\%) = 431,000 \, Ω \) |
**Use Ohm’s Law: \( R = V/I \)**
- **Calculate the Resistances Using Ohm’s Law:**
- \( R_1 = \frac{V_1}{I_1} = \frac{2.79}{2.05} = 1.36 \, Ω \)
- \( R_2 = \frac{V_2}{I_2} = \frac{2.8}{2.12} = 1.32 \, Ω \)
- **Calculate the Equivalent Resistance Using the Parallel Resistance Formula:**
\[
\frac{1}{R_e} = \frac{1}{R_1} + \frac{1}{R_2}
\]
Consider the values of resistance provided by the color code.
\[
R_e = \frac{430,000 \cdot 1,000}{430,000 + 1,000} = \text{calculated value}
\]
- **Determine Your % Error Between the Two Values Found for the Total Resistance:**
\[
\text{Error} = \left( \
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