1. We restrict the function secz on [0, /2) U[, 3/2) to get an one-to-one function. We call it f(x). We define the inverse of this function to be f-¹(r). (a) Find the domain and range of f-1. No need to justify your answer to this part. Final Answer Final Answer Domain: Range: (b) Compute f-¹(sec 5) and sec(f-¹(5)). No need to justify your answer to this part. Final Answer Final Answer
1. We restrict the function secz on [0, /2) U[, 3/2) to get an one-to-one function. We call it f(x). We define the inverse of this function to be f-¹(r). (a) Find the domain and range of f-1. No need to justify your answer to this part. Final Answer Final Answer Domain: Range: (b) Compute f-¹(sec 5) and sec(f-¹(5)). No need to justify your answer to this part. Final Answer Final Answer
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.5: Graphs Of Functions
Problem 36E
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Please answer part E of this homework practice question. For Part A, I and my friends got D: (inf,-1]U[1,inf]; R: [0,pi/2)U[pi,3pi/2). For Part B, we got f^(-1) (sec5) =2pi-5; sec (f(-1)(5)) = 5. I hope this helps in answering Part E. Thank you
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