1. Two concentric spherical surfaces enclose a point charge q. The radius of the outer sphere is twice that of the inner one. a. Is the electric field of the inner surface is greater than, less than, or equal to the electric field of the inner surface? Use a drawing to justify your answer. b. Is the electric flux of the inner surface is greater than, less than, or equal to the electric field of the inner surface? Use a drawing to justify your answer.
1. Two concentric spherical surfaces enclose a point charge q. The radius of the outer sphere is twice that of the inner one. a. Is the electric field of the inner surface is greater than, less than, or equal to the electric field of the inner surface? Use a drawing to justify your answer. b. Is the electric flux of the inner surface is greater than, less than, or equal to the electric field of the inner surface? Use a drawing to justify your answer.
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
Transcribed Image Text:1. Two concentric spherical surfaces enclose a point charge q. The radius of the outer
sphere is twice that of the inner one.
a.
Is the electric field of the inner surface is greater than, less than, or equal to the
electric field of the inner surface? Use a drawing to justify your answer.
b. Is the electric flux of the inner surface is greater than, less than, or equal to the
electric field of the inner surface? Use a drawing to justify your answer.
Expert Solution

Step 1
Concept used:-
Electric field due to point charge = K(Q) /R^2 , at a distance R from the center.
Electric flux through a Gaussian surface is independent of the size of surface and equals to charge inclosed divided be epsilon not.
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