1. The unity feedback system has a transfer function C(s) G(s) = K E(s) s(s+ a) and is to follow a ramp input, r(t) = tu(t), so that the steady-state output position differs from the input position by 0.01 of the input velocity (e.g., e(oo) = 1/K, = 0.01). The natural frequency of the closed-loop system will be w₁ = 5 rad/s. Answer the following questions (a) The system type (b) The values of K and a (c) The closed-loop system's damping ratio (<)
1. The unity feedback system has a transfer function C(s) G(s) = K E(s) s(s+ a) and is to follow a ramp input, r(t) = tu(t), so that the steady-state output position differs from the input position by 0.01 of the input velocity (e.g., e(oo) = 1/K, = 0.01). The natural frequency of the closed-loop system will be w₁ = 5 rad/s. Answer the following questions (a) The system type (b) The values of K and a (c) The closed-loop system's damping ratio (<)
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![1. The unity feedback system has a transfer function
G(s) =
C(s) K
=
E(s) s(s+ a)
and is to follow a ramp input, r(t) = tu(t), so that the steady-state output position
differs from the input position by 0.01 of the input velocity (e.g., e(oo) = 1/K, = 0.01).
= 5 rad/s.
The natural frequency of the closed-loop system will be w
Answer the following questions
(a) The system type
(b) The values of K and a
(c) The closed-loop system's damping ratio (2)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd7bc6c6a-7bd2-4c26-8077-4c1d0571e1a5%2F04b22a71-1cc7-493d-bca2-a81d607f4d64%2Feu789p9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. The unity feedback system has a transfer function
G(s) =
C(s) K
=
E(s) s(s+ a)
and is to follow a ramp input, r(t) = tu(t), so that the steady-state output position
differs from the input position by 0.01 of the input velocity (e.g., e(oo) = 1/K, = 0.01).
= 5 rad/s.
The natural frequency of the closed-loop system will be w
Answer the following questions
(a) The system type
(b) The values of K and a
(c) The closed-loop system's damping ratio (2)
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