Answer complete 1. The synthesis of n-butylacetate is shown below.H2SO4НОOH-H2OWith reference to the Twelve Principles of Green Chemistry,а.state one way in which the synthesis of n-butylacetate was green.b.state one way in which the synthesis of n-butylacetate was not green.c.state one way which the synthesis of n-butylacetate can be 'greener'.d.calculate the AE.

(a) Answer - According to the question - Given From 6th principle ‘Design for energy efficiency’,…

Answered: 1. The synthesis of n-butylacetate is…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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With the image attached please do the calculations/calculate what is highlighted in yellow please Please also calculate - percent % error in molar mass - percent % error in pKa Please please please answer as fast as possible
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Trial I Trial II Final reading HCI 26. 40 ml 27.10 ml Initial reading HCI 1.2 ml 1.8 ml Volume of HCl used ? ? Final reading NaOH 33.7 ml 32.8 ml Initial reading NaOH 0.8 mL 0.5 ml Volume of NaOH used ? ? For trial I: Normality of NaOH : 0.25 N Vol. of HCl used = final volume - initial volume Solve for the average Normality of HCI : ? NHCI x VHCI = NNAOH x VNAOH Vol. of NaOH used = final volume - initial volume NNAOH x VNAOH For trial II: NHCI = Vol. of HCl used = final volume - initial volume VHCI Activa Vol. of NaOH used = final volume - initial volume Go to S
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1. The synthesis of n-butylacetate is shown below. H2SO4 + НО HO. -H2O With reference to the Twelve Principles of Green Chemistry, state one way in which the synthesis of n-butylacetate was green. a.