1). The susceptibility of FeCl₂ obeys the Curie-Weiss law over the temperature range 90 K to room temperature (293K), with 0 =48K. Its molecular susceptibility at room temperatur is 1.475 1022 emu/Oe g mol). (Use: N= 6.022 x 1023 atoms/g-mol, KB= 1.38 x 10-¹6 erg/K) (a) Show that the effective magnetic moment is 5.4 µB. (b) Show that the value of J is 2.25. (c) At an applied field of 8000 Oe, what is the value of the molecular field at 0 °C ?

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1). The susceptibility of FeCl₂ obeys the Curie-Weiss law over the temperature range
90 K to room temperature (293K), with 0 =48K. Its molecular susceptibility at room temperature
is 1.475 1022 emu/Oe g mol). (Use: N= 6.022 x 1023 atoms/g-mol, KB= 1.38 × 10-¹6 erg/K)
(a) Show that the effective magnetic moment is 5.4 µB.
(b) Show that the value of J is 2.25.
(c) At an applied field of 8000 Oe, what is the value of the molecular field at 0 °C ?
Transcribed Image Text:1). The susceptibility of FeCl₂ obeys the Curie-Weiss law over the temperature range 90 K to room temperature (293K), with 0 =48K. Its molecular susceptibility at room temperature is 1.475 1022 emu/Oe g mol). (Use: N= 6.022 x 1023 atoms/g-mol, KB= 1.38 × 10-¹6 erg/K) (a) Show that the effective magnetic moment is 5.4 µB. (b) Show that the value of J is 2.25. (c) At an applied field of 8000 Oe, what is the value of the molecular field at 0 °C ?
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