**Statistics and Data Analysis Problems**1. **Test Score Selection** The scores on a test have a mean of 100 and a standard deviation of 15. If a personnel manager wishes to select from the top 75% of applicants who take the test, find the cutoff score.2. **Charitable Contributions Analysis** The average charitable contribution itemized per income tax return in Pennsylvania is $792. Suppose that... (continued text not visible).---*Explanation of Concepts:*- **Mean**: The average of all data points.- **Standard Deviation**: Measures the dispersion of data points from the mean.*Example Calculation*:To find the cutoff score for the top 75% of applicants, you can use the following steps:1. Determine the Z-score corresponding to the 25th percentile (since you want the top 75%).2. Apply the Z-score formula: $ X = \mu + Z\sigma $.Where:- $ X $ is the cutoff score,- $ \mu $ is the mean,- $ Z $ is the Z-score.- $ \sigma $ is the standard deviation.Refer to a Z-table to find the Z-score for the 25th percentile (approximately -0.674).Example calculation:$ X = 100 + (-0.674 \times 15) $$ X = 100 - 10.11 $$ X \approx 89.89 $*Cutoff score*: Approximately 90 (to be from the top 75%).

Answered: 1. The scores on a test have a mean of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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1. According to one study, the average hours of sleep on a weeknight for men was 6.9 hours with a standard deviation of 1.5 hours. a. Find the proportion of men who sleep for more than 8 hours per night. b. Find the proportion of men who sleep for less than 6 hours per night. c. Find the proportion of men who sleep between 6-8 hours per night. d. Find the number of hours that represents the 90th percentile.
The mean IQ of 200,000 current and past University of Manitoba students has been found to be 81.9. The standard deviation was found to be 13.1. The student enrollment at the University of Manitoba in 2016 was 29,987. The minimum IQ to be able to graduate from the University of Winnipeg has been found to be 104. Of the 29,987 students at the University of Manitoba in 2016, how many would be expected to be smart enough to graduate from the University of Winnipeg? Assume a Gaussian distribution.
1. higher or lower 2. Slower or faster
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Find the mean and standard deviation of the following numbers: 35,18,12,32,35,75,32,26,18
Assume that the mathematics scores on the SAT are normally distributed with a mean of 500 and a standard deviation of 100. What percent of students who took the test have a mathematics score between 590 and 640? FAUTE E CEL Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table. a S ........ % of students who took the test have a mathematics score between 590 and 640. (Round to two decimal places as needed.).
Imagine that for those who meditate daily, the number of minutes in meditation has mean 35 and standard deviation 10. In a group of 200 such persons, how many are expected to meditate more than 43 minutes per day? Click the icon to view the table of z-scores. Of the 200 persons, approximately will meditate more than 43 minutes per day. (Round to the nearest whole number as needed.)
• - Find the mean deviation for the following data set {7,23,11,44,46,23,28,30,32,43,47}
Q21. For the Given values of 91.9, 84, 88.5, 86.8, 89.4,83.6, 80.2, 88.1, 88.5, 93.1 and 93.8 ,Calculate (i) Mean (ii) Algebraic Sum of deviation (iii) Variance (iv)Standard Deviation. i) Mean = ii) Sum of Deviation= iii) Variance = iv) Standard Deviation =
4. A college instructor gave identical tests to two randomly sampled groups of 50 students. One group took the test on paper and the other took it online. Those who took the test on paper had an average score of 75.0 with a standard deviation of 12.5. those who took the test online had an average score of 78.0 with a standard deviation of 14.0. can you conclude that the mean scores differ between online and paper tests?

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1. The scores on a test have a mean of 100 and a standard deviation of 15. If a personnel manager wishes to select from the top 75% of applicants who take the test, find the cutoff score.