1. The position of a particle as a function of time is given by * = [(5t2 – 2t)î + (t? – 8t)ĵ + (3t? + 1)k] m, wheret is in seconds. (a) Calculate (r, x r5) · r2, where r, r3 and rg are the position vectors of the particle at time 2 sec, 3 sec and 5 sec respectively. (b) Find A such that (r – 2A) – (r3- 7) = 0. (c) Calculate the angle between Á and rz.

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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1. The position of a particle as a function of time is given by
i = [(5t? – 2t)î + (t² – 8t)j + (3t² + 1)k] m, where t is in seconds.
(a) Calculate (rx r3) · 2, where r, r and rg are the position vectors of the particle at
time 2 sec, 3 sec and 5 sec respectively.
(b) Find A such that (r – 2A) – (r3 - r;) = 0.
(c) Calculate the angle between Á and r.
Transcribed Image Text:1. The position of a particle as a function of time is given by i = [(5t? – 2t)î + (t² – 8t)j + (3t² + 1)k] m, where t is in seconds. (a) Calculate (rx r3) · 2, where r, r and rg are the position vectors of the particle at time 2 sec, 3 sec and 5 sec respectively. (b) Find A such that (r – 2A) – (r3 - r;) = 0. (c) Calculate the angle between Á and r.
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