1. The Maxwell-Boltzmann distribution of speeds is 3 m mv² f (v) = 4T 2 v²e 2kT \2tkT) a) Calculate the fraction of CO2 molecules at 300K between 100 and 105 m/s. b) Repeat for 600 and 605 m/s. c) Repeat a) and b) at T=1000K.
1. The Maxwell-Boltzmann distribution of speeds is 3 m mv² f (v) = 4T 2 v²e 2kT \2tkT) a) Calculate the fraction of CO2 molecules at 300K between 100 and 105 m/s. b) Repeat for 600 and 605 m/s. c) Repeat a) and b) at T=1000K.
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![**The Maxwell-Boltzmann Distribution of Speeds**
The Maxwell-Boltzmann distribution of speeds is given by the equation:
\[
f(v) = 4\pi \left( \frac{m}{2\pi k T} \right)^{\frac{3}{2}} v^2 e^{-\frac{mv^2}{2kT}}
\]
**Problems:**
a) Calculate the fraction of CO\(_2\) molecules at 300K with speeds between 100 and 105 m/s.
b) Repeat for speeds between 600 and 605 m/s.
c) Repeat both a) and b) at a temperature of T = 1000K.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0e989a36-a976-4f9a-8f93-2801096d9bdd%2F583be82c-cf87-4404-ba4d-a1b3174eef2a%2Fguzqikt_processed.png&w=3840&q=75)
Transcribed Image Text:**The Maxwell-Boltzmann Distribution of Speeds**
The Maxwell-Boltzmann distribution of speeds is given by the equation:
\[
f(v) = 4\pi \left( \frac{m}{2\pi k T} \right)^{\frac{3}{2}} v^2 e^{-\frac{mv^2}{2kT}}
\]
**Problems:**
a) Calculate the fraction of CO\(_2\) molecules at 300K with speeds between 100 and 105 m/s.
b) Repeat for speeds between 600 and 605 m/s.
c) Repeat both a) and b) at a temperature of T = 1000K.
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