1. The iodide in a sample that also contained chloride was converted to iodate by treatment with an excess of bromine: 3H,O + 3Br, + I¯ → 6Br + I0,¯ + 6H+ The unused bromine was removed by boiling; an excess of barium ion was then added to precipitate the iodate: Ba?+ + 2IO, Ba(IO3), In the analysis of a 2.0375 g sample, 0.0678 this analysis as percent potassium iodate. g barium iodate was recovered. Express the results of

1. The iodide in a sample that also contained chloride was converted to iodate by treatment with an excess of bromine: 3H,O + 3Br, + I¯ → 6Br + I0,¯ + 6H+ The unused bromine was removed by boiling; an excess of barium ion was then added to precipitate the iodate: Ba?+ + 2IO, Ba(IO3), In the analysis of a 2.0375 g sample, 0.0678 this analysis as percent potassium iodate. g barium iodate was recovered. Express the results of

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Can you explain plz?
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