### Understanding Standard Normal Distribution#### Reference GraphUse the graph of the Standard Normal Distribution above for reference. In questions 7-10, shade the area described. Include only the z score (or scores) mentioned in the question.Next, load Statdisk, click OK, and minimize the Sample Editor Window. Then, select Analysis, Probability Distributions, and Normal Distribution. Let \( z = 3 \) and click Evaluate. All of the answers you need for questions 7-10 are on the screen.**Remember: Do not round the answers! Show all decimal places!**---#### Graph ExplanationThe Standard Normal Distribution graph (Figure 6-4) depicts a bell-shaped curve centered around a mean of zero. The x-axis represents the z score (standard deviations from the mean), ranging from -3 to 3. The y-axis represents the probability density. The highest point on the graph is at \( z = 0 \), which corresponds to the mean of the distribution.#### Questions7. **The region from \( z = -\infty \) to \( z = 3 \)** ![Normal Curve](part_of_curve.png) `Area ______________________` - Shade the area under the curve from the leftmost end of the graph (approaching negative infinity) to \( z = 3 \).8. **The region from \( z = 3 \) to \( z = \infty \)** ![Normal Curve](another_part_of_curve.png) `Area ______________________` - Shade the area under the curve from \( z = 3 \) to the rightmost end of the graph (approaching infinity).---### Instructions Recap:1. **Use the provided Standard Normal Distribution graph.**2. **Shade the indicated regions.**3. **Use Statdisk to compute the area for the regions specified in the questions without rounding the answers.**### Note: Ensure to demonstrate all decimal places in your answers as specified.---This guide aims to help you effectively utilize the Standard Normal Distribution graph for statistical analysis and calculate probabilities accurately using Statdisk. ### Chapter 7#### InstructionsLoad Statdisk, click OK, and minimize the Sample Editor. Select Analysis, Confidence Intervals, and Proportion One Sample. Give only the confidence interval in your answer.**DO NOT ROUND YOUR ANSWERS!! SHOW ALL DECIMAL PLACES!!**#### Problems**9.** The region from \( z = -\infty \) to \( z = -3 \) & the region from \( z = 3 \) to \( z = \infty \). _Area: _______________________(Graph: Symmetrical bell curve representing a normal distribution with shaded areas in the far left and far right tails beyond \( z = -3 \) and \( z = 3 \) respectively.)**10.** The region between \( z = -3 \) and \( z = 3 \). _Area: _______________________(Graph: Symmetrical bell curve representing a normal distribution with the central area between \( z = -3 \) and \( z = 3 \) shaded.)#### Exercises1. The Hartford Insurance Company wants to estimate the percentage of drivers who change tapes or CDs while driving. A random sample of 850 drivers results in 544 who change tapes or CDs while driving. Find a 90% interval estimate of the percentage of all drivers who change tapes or CDs while driving. _________________________________________________________________2. When 500 college students are randomly selected and surveyed, it is found that 135 of them own personal computers. Find a 95% confidence interval for the true proportion of all college students who own personal computers. _________________________________________________________________

Answered: 1. The Hartford Insurance Company wants…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Your statistics instructor claims that 60 percent of the students who take her Elementary Statistics class go through life feeling more enriched. For some reason that she can't quite figure out, most people don't believe her. You decide to check this out on your own. You randomly survey 64 of her past Elementary Statistics students and find that 34 feel more enriched as a result of her class. Construct a 95% confidence interval for the true mean or proportion. Round to the nearest hundredth (2 decimal places). ( , )
9. A researcher wants to construct a 99% confidence interval for the proportion of Americans who think that the U.S. invading Iraq was an effective step in combating world terrorism. She has no initial idea of what that proportion is. How large should her sample size be if she wants the margin of error to be at most two percent? Show or explain your thinking.
24. Job Interviews In a Harris poll of 514 human resource professionals, 90% said that the appearance of a job applicant is most important for a good first impression. a. Among the 514 human resource professionals who were surveyed, how many of them said that the appearance of a job applicant is most important for a good first impression? b. Construct a 99% confidence interval estimate of the proportion of all human resource professionals believing that the appearance of a job applicant is most important for a good first impression. c. Repeat part (b) using a confidence level of 80%. d. Compare the confidence intervals from parts (b) and (c) and identify the interval that is wider. Why is it wider?
2. According to the website Rotten Tomatoes, 94% of people who watched the Netflix show Stranger Things liked it. Since UR students tend to be scientifically minded, we hypothesize that less than 94% of UR students like the show. Out of 219 surveyed UR students, 198 indicated they like Stranger Things. Use the built in prop.test() function to: a. Construct a 90% confidence interval for the proportion of UR students who like Stranger Things. b. Test at the a=0.10 significance level whether the proportion of students who like Stranger Things is LESS THAN 0.94. What conclusion do you reach?
A newspaper reported on the topics that teenagers most want to discuss with their parents. The findings, the results of a poll, showed that 41% would like more discussion about the family's financial situation, 11% would like to talk about school, and 43% would like to talk about religion. These and other percentages were based on a national sampling of 393 teenagers. Write the margin of error for a 90% confidence interval that estimates the proportion of all teenagers who want more family discussions about school. Round to the nearest thousandth.
10. Several years ago, 51% of parents who had children in grades K-12 were satisfied with the quality of education the students receive. A recent poll asked 1,075 parents who have children in grades K-12 if they were satisfied with the quality of education the students receive. Of the 1,075 surveyed, 472 indicated that they were satisfied. Construct a 99% confidence interval to assess whether this represents evidence that parents' attitudes toward the quality of education have changed. What are the null and alternative hypotheses? Ho: p (1) versus H1: p (2) (Round to two decimal places as needed.) Use technology to find the 99% confidence interval. The lower bound is The upper bound is (Round to two decimal places as needed.) What is the correct conclusion? O A. Since the interval contains the proportion stated in the null hypothesis, there is insufficient evidence that parents' att O B. Since the interval contains the proportion stated in the null hypothesis, there is sufficient…
1. Explain how to find a confidence interval for a population proportion using StatCrunch. 2. Explain how to find the margin of error given a confidence interval for a population proportion.
A. Suppose we wish to make an estimate of the proportion of the population that has ever been arrested. We take a random sample of 500 people. In this sample, 10% of the respondents report having ever been arrested. Construct a 95% confidence interval for the proportion of people in the population who have been arrested. 2. Interpret, in words, the meaning of this interval.
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