**Problem Statement:**1. The formation constant for the lead(II)-EDTA chelate, PbY²⁻, is 1.10 x 10¹⁸. Calculate the conditional formation constant (K'f) at: (a) pH = 3.00, and (b) pH = 10.0.

The expression for calculating the conditional formation constant is as follows, Kf' = Kf × αY4- Given: Formation constant for PbY2- = 1.10×1018(a) pH = 3.00 To find the conditional formation constant as follows, At pH = 3, αY4- = 2.6×10-11Kf = 1.10×1018 Substituting the values in the following equation, Kf' = Kf × αY4-= 2.6×10-111.10×1018Kf' = 2.86×107 Therefore, the conditional formation constant at pH = 3 is 2.86 x 107. (b) pH =10.0 To find the conditional formation constant as follows, At pH = 10, αY4- = 0.36Kf = 1.10×1018 Substituting the values in the following equation, Kf' = Kf × αY4-= 0.361.10×1018Kf' = 3.96×1017 Therefore, the conditional formation constant at pH = 10 is 3.96 x 1017.

Answered: 1. The formation constant for the…

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1. The formation constant for the lead(II)-EDTA chelate, PbY2, is 1.10 x 1018. Calculate the conditional formation constant (K/) at: (a) pH = 3.00, and (b) pH = 10.0.

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**Problem Statement:**

1. The formation constant for the lead(II)-EDTA chelate, PbY²⁻, is 1.10 x 10¹⁸. Calculate the conditional formation constant (K'f) at:
(a) pH = 3.00, and
(b) pH = 10.0.

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