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1. The electrical power p(t), in kilowatts, being used by a household as a function of time t, in hours, is modelled by a graph where t = 0 corresponds to 06:00. The graph indicated peak use at 08:00 and a power failure between 09:00 and 10:00. a) Determine p(0). b) Determine limp(t) t->2 ↑p(t) 10- 0 06:00 -N 2 we 4 6 12:00

1. The electrical power p(t), in kilowatts, being used by a household as a function of time t, in hours, is modelled by a graph where t = 0 corresponds to 06:00. The graph indicated peak use at 08:00 and a power failure between 09:00 and 10:00. a) Determine p(0). b) Determine limp(t) t->2 ↑p(t) 10- 0 06:00 -N 2 we 4 6 12:00

Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter8: Introduction To Functions
Section8.8: Linear And Quadratic Functions
Problem 2WE
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1. The electrical power p(t), in kilowatts, being used by a household as a function of time t, in hours, is modelled by a graph where t = 0 corresponds to 06:00. The graph indicated peak use at 08:00 and a power failure between 09:00 and 10:00. a) Determine p(0). b) Determine limp(t) t->2 ↑p(t) 10- 0 06:00 -N 2 we 4 6 12:00
Transcribed Image Text:1. The electrical power p(t), in kilowatts, being used by a household as a function of time t, in hours, is modelled by a graph where t = 0 corresponds to 06:00. The graph indicated peak use at 08:00 and a power failure between 09:00 and 10:00. a) Determine p(0). b) Determine limp(t) t->2 ↑p(t) 10- 0 06:00 -N 2 we 4 6 12:00
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