1. The cross-sectional area of each member of the truss is 1400 mm². Calculate the stresses in members DF, CE, and BD. В D 6 m 4 m A 4 m C 3 m Е 3m 100 kN 200 kN
1. The cross-sectional area of each member of the truss is 1400 mm². Calculate the stresses in members DF, CE, and BD. В D 6 m 4 m A 4 m C 3 m Е 3m 100 kN 200 kN
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
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- YOUR SUB ANSWERS MUST BE IN 6 DECIMAL PLACES.
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![1. The cross-sectional area of each member of the truss is 1400 mm2.
Calculate the stresses in members DF, CE, and BD.
В
D
6 m
4 m
A
F
4 m
C
3 m
Е 3m
100 kN
200 kN](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1138f7d1-22a7-47c2-8351-9a91cd8d259f%2F5d2b598b-510e-4567-8f9a-762118398c87%2Fsf8btj4_processed.png&w=3840&q=75)
Transcribed Image Text:1. The cross-sectional area of each member of the truss is 1400 mm2.
Calculate the stresses in members DF, CE, and BD.
В
D
6 m
4 m
A
F
4 m
C
3 m
Е 3m
100 kN
200 kN
![Sample Problem 2
I kip
The bars of the truss have a cross-sectional area of 1.25 in2.
Determine the average normal stress in members AB and BE due
to the loading P = 8 kip. State whether the stress is tensile or
compressive.
B
3 ft
A
E
4 ft
4 ft
0.75 P= G kiPs
P = 8kipS
1
2. Normal Stress
3
4
5
В
Sample Problem 2
3 ft
Given:
P = 8 kip
A = 1.25 in?
Required: OAB, O BE
A
E
4 ft
4 ft-
0.75 P
Solution:
* Jont A
FAB
+ Joint E
Fre (를) 8.0
FAB - 13 3333 Kips T
BE
FAE
FED
FAE
FBE - 6:0
FBE: Gkips, I
Co kips
Gkips
FBE
FAB 13:3533kipS
BE:4.8ksi, T
A
1-25 in
1
2. Normal Stress
3
4
6.
Sample Problem 3
Three forces, each of magnitude P = 4 kN, are applied to the
mechanism shown. Determine the cross-sectional area of the
uniform portion of rod BE for which the normal stress in that
portion is +100 MPa.
0.100 m
P
P
|B
C
0.150 m
0.300 m
0.250 m
1
2. Normal Stress
3
4
6.
0.100 m
Sample Problem 3
P
Given:
P = 4 kN
B
+100 MPa
OBE
Required: ABE
Solution:
0.150 m
0.300 m
0.250 m
p.yKN
P:4KN
Cx
'cy
Dy
1
2. Normal Stress
3
4
6.
0.100 m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1138f7d1-22a7-47c2-8351-9a91cd8d259f%2F5d2b598b-510e-4567-8f9a-762118398c87%2Faorg479_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Sample Problem 2
I kip
The bars of the truss have a cross-sectional area of 1.25 in2.
Determine the average normal stress in members AB and BE due
to the loading P = 8 kip. State whether the stress is tensile or
compressive.
B
3 ft
A
E
4 ft
4 ft
0.75 P= G kiPs
P = 8kipS
1
2. Normal Stress
3
4
5
В
Sample Problem 2
3 ft
Given:
P = 8 kip
A = 1.25 in?
Required: OAB, O BE
A
E
4 ft
4 ft-
0.75 P
Solution:
* Jont A
FAB
+ Joint E
Fre (를) 8.0
FAB - 13 3333 Kips T
BE
FAE
FED
FAE
FBE - 6:0
FBE: Gkips, I
Co kips
Gkips
FBE
FAB 13:3533kipS
BE:4.8ksi, T
A
1-25 in
1
2. Normal Stress
3
4
6.
Sample Problem 3
Three forces, each of magnitude P = 4 kN, are applied to the
mechanism shown. Determine the cross-sectional area of the
uniform portion of rod BE for which the normal stress in that
portion is +100 MPa.
0.100 m
P
P
|B
C
0.150 m
0.300 m
0.250 m
1
2. Normal Stress
3
4
6.
0.100 m
Sample Problem 3
P
Given:
P = 4 kN
B
+100 MPa
OBE
Required: ABE
Solution:
0.150 m
0.300 m
0.250 m
p.yKN
P:4KN
Cx
'cy
Dy
1
2. Normal Stress
3
4
6.
0.100 m
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