1. The conversion of the concentrations into the required expression is as follows: Concentration given Expression required 0.5% NaCl molarity 1 mM of KBr mg/ml 5 mg/100 ml paracetamol Molarity 0.15 N H2SO4 g/litre 0.5% ethanol/water (w/v) ppm
1. The conversion of the concentrations into the required expression is as follows: Concentration given Expression required 0.5% NaCl molarity 1 mM of KBr mg/ml 5 mg/100 ml paracetamol Molarity 0.15 N H2SO4 g/litre 0.5% ethanol/water (w/v) ppm
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter18: Carboxylic Acids
Section: Chapter Questions
Problem 18.17P: 18-17 Hexanoic (caproic) acid has a solubility in water of about 1 g/100 mL water. Which part of the...
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1. The conversion of the concentrations into the required expression is as follows:
Concentration | given Expression required |
0.5% NaCl | molarity |
1 mM of KBr | mg/ml |
5 mg/100 ml paracetamol | Molarity |
0.15 N H2SO4 | g/litre |
0.5% ethanol/water (w/v) | ppm |
2. 0.641 g of a semi-synthetic alkaloid was dissolved in 25 ml of 1% w/v acetic acid and was
analysed directly by HPLC. The solution was found to contain 1.42 mg/100 ml of an impurity.
What is the level of impurity in % w/w and ppm?
3. Calculate the pH of a buffer system made by dissolving 1.2 g of acetic acid and 0.82 g of
sodium acetate in 500 ml of distilled water (pKa of acetic acid = 4.7)
0.641 g of a semi-synthetic alkaloid was dissolved in 25 ml of 1% w/v acetic acid and was
analysed directly by HPLC. The solution was found to contain 1.42 mg/100 ml of an impurity.
What is the level of impurity in % w/w and ppm?
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