1. The bearing of a back tangent of a simple curve is N 65°00' E, while the forward tangent has a bearing of S 75° 00' E. The tangent distance is 50.00 m. The stationing of the Point of Curvature is at 10 + 235.48. Compute the following: Stationing of Vertex (PI) Stationing of Point of Tangency (PT) Length of Chord from PC to Station A (10+300) subchord distance (c2) deflection angle of subchord (c1) PI

Q: The line connecting the PC and PT of the simple curve is 120.4m. The radius is 213.6m. If the…

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Q: The curve y= x* bounds the shaded 600 section on top. The vertical lines X = 2 in. and x = 5 in.…

A: Given Data: The equation of the curve is y=x4. The limit of curve in X-direction is 2 in. to 5 in.…

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