1. The azimuths of the back and forward tangents of a simple curve respectively are 257° 25' and 2940 05. The long chord of the simple curve is 123.147 meters and stationing of V is at station 50 + 134.

Q: A simple horizontal curve has 35 degrees of curvature and subtends an angle of 110 degrees. If the…

A: Degrees of curvature, D = 35°PC is at station  = 3 + 65.00 ft

Q: The perpendicular distance between the two parallel tangents of a reversed curve is 8 m. and the…

A:

Q: The common tangent of AB of a compound curve is 76.42 m, with an azimuth of 268 30'.The vertex V…

A:

Q: The common tangents BC of a reverse curve is 280.5 m and has a bearing of S 47o31’E. AB is the…

A: Given common tangents BC of a reverse curve , T is -280.5 m Stationing of PI=12+523.37

Q: 6. A compound curve has a central angle of the first curve equal to 40° and a radius of 280m. while…

A: R1 = 280m D2 = 5NOTE : As per guidelines, first question is solved. Request you to post remaining…

Q: A compound curve connects three tangents having an azimuths of 250°, 270 ° and 290° respectively.…

A: The given data is: The azimuths are 250°, 270 °, and 290° The length of the chord=340m

Q: The tangent at the beginning of the curve at the P.C. is 125.70 m long and that at the P.T. is 155.6…

A:

Q: A reversed curve is connecting the two tangent lines AB and CD having directions of due East and S…

A: given data,radius of first curve=200mradius of second curve=400mIED =300m long…

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