1. Suppose that Jerry (a baker) wants to find a 95% Confidence Interval for the mean baking time for all of his jelly donuts. He takes a random sample of 40 jelly donuts over the course of several weeks. He found that the average baking time of the sample was 19.2 minutes with a standard deviation of 1.8 minutes. a. Find the 95% confidence interval. b. Interpret the interval in context. c. Find the error bound of the interval. d. Suppose Jose, another donut maker, states that his jelly donuts have a mean baking time of 18 minutes. Is there evidence at the 95% confidence level, to support the claim that the mean baking times for all Jerry’s and Jose’s jelly donuts are different? **Justify.**

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Answered: 1. Suppose that Jerry (a baker) wants…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The Athletics Department at a high school is interested in the difference in the run times between 11th and 12th grade students. Suppose the 11th grade students make up the first sample while the 12th grade students make up the second.Using a confidence level of 95%, the confidence interval found was (−1.8,2.9)(-1.8,2.9).Which of the following is the correct interpretation? We are 95% confident that the run times of the 11th grade students are, on average, faster than those of the 12th grade students. We are 95% confident that the run times of the 11th grade students are, on average, slower than those of the 12th grade students. We are 95% confident that the run times of the 11th grade students are, on average, about the same as those of the 12th grade students.
1. A recent study of 22 motorists showed that they spent an average of P750 per week. The standard deviation of the sample was P90. Find the 99% confidence interval of the true mean. Solution: 2. A sample of 15 National Collegiate Athletics Association (NCAA) basketball players had an average height of 6 feet with a sample standard deviation of 0.80 foot. Find the 90% confidence interval of the true mean height of all players. Solution:
You are interested in constructing a 90% confidence interval for the proportion of all caterpillars that eventually become butterflies. Of the 427 randomly selected caterpillars observed, 45 lived to become butterflies. a. Use 3 decimal places to complete the following statement: With 90% confidence the proportion of all caterpillars that lived to become a butterfly is between and . b. If many groups of 427 randomly selected caterpillars were observed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population proportion of caterpillars that become butterflies and about percent will not contain the true population proportion.
Suppose you are told that a 95% confidence interval for the average price of a gallon of regular gasoline in your state is from $3.37 to $4.18. Use the fact that the confidence interval for the mean is in the form x − E to x + E to compute the sample mean and the maximal margin of error E. (Round your answers to two decimal places.) x=$ E=$
You are interested in constructing a 95% confidence interval for the proportion of all caterpillars that eventually become butterflies. Of the 390 randomly selected caterpillars observed, 60 lived to become butterflies. Round answers to 4 decimal places where possible. a. With 95% confidence the proportion of all caterpillars that lived to become a butterfly is between and . b. If many groups of 390 randomly selected caterpillars were observed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population proportion of caterpillars that become butterflies and about percent will not contain the true population proportion.
tion. Use this information to construct the 90% and 95% confidence intervals fc of the confidence intervals. ce of a certain stock was $123.13. Assume the population standard deviation is
Suppose that you wanted to know if the percentage of people who will attend a sporting event this year will decrease. Last year, 43% of Americans attended a sporting event. After taking a sample, you attain a sample percentage of 18% with a margin of error of 3%. Construct a confidence interval and use that interval to determine if the number of Americans who will attend a sporting event has decreased. Show your calculation for the interval and then state your conclusion in complete sentences.
Suppose a researcher takes a random sample of 1,000 students from a university and creates a 95% confidence interval for the true proportion of left handed students at the university. Which of the following is true about this interval when compared with a 95% confidence interval based on a random sample of 600 students from the same university? a. The interval based on a sample of 600 students will be wider than the interval based on a sample of 1,000 students. b. The lower and upper endpoints of the 95% CI based on 600 students will both be larger than the corresponding lower and upper endpoints of the 95% CI based on 1,000 students. c. 95% CIs based in samples of 1,000 students are more likely to include the true population proportion than 95% CIs based on samples of 600 students. d. The interval based on a 1,000 students will be wider than the interval based on 600 students. 2. If the researchers above wished to decrease the width of the mean confidence interval for the mean age…
A researcher is interested in finding a 90% confidence interval for the mean number of times per day that college students text. The study included 115 students who averaged 34.2 texts per day. The standard deviation was 23.3 texts. a. To compute the confidence interval use a distribution. b. With 90% confidence the population mean number of texts per day is between and texts. c. If many groups of 115 randomly selected members are studied, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population number of texts per day and about percent will not contain the true population mean number of texts per day.
Please solve the a, b, c, and d.

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