4 1. Suppose that in the experiment of the empirical formula 10% of the metal (Mg) stays unreacted and doesnot get converted to oxide, how this error will affect the reported mass of:(a) Magnesium in the sample? Explain.(b) Oxygen in the sample? Explain.2. When the magnesium is not allowed sufficient air (oxygen) in step (4) some magnesium nitride(Mg3N2 ) forms. If the MgsN2 is not decomposed in step (6), will the reported Mg to O mole ratio behigh or low? Explain.

Magnesium being a metal reacts with oxygen to form magnesium oxide.

1. Suppose that in the experiment of the empirical formula 10% of the metal (Mg) stays unreacted and does not get converted to oxide, how this error will affect the reported mass of: (a) Magnesium in the sample? Explain. (b) Oxygen in the sample? Explain.

1. Suppose that in the experiment of the empirical formula 10% of the metal (Mg) stays unreacted and does not get converted to oxide, how this error will affect the reported mass of: (a) Magnesium in the sample? Explain. (b) Oxygen in the sample? Explain.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

1. Suppose that in the experiment of the empirical formula 10% of the metal (Mg) stays unreacted and does
not get converted to oxide, how this error will affect the reported mass of:
(a) Magnesium in the sample? Explain.
(b) Oxygen in the sample? Explain.
2. When the magnesium is not allowed sufficient air (oxygen) in step (4) some magnesium nitride
(Mg3N2 ) forms. If the MgsN2 is not decomposed in step (6), will the reported Mg to O mole ratio be
high or low? Explain.

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