1. Suppose a car is involved in a collision in which it is brought to a constant speed of 31 m/s. Fortunately, the seat belt worn by the 65 kg driver brought the driver to rest in 0.35 s. How much force is exerted by the seat on the driver? Compute for the acceleration experienced by the driver during collision.
1. Suppose a car is involved in a collision in which it is brought to a constant speed of 31 m/s. Fortunately, the seat belt worn by the 65 kg driver brought the driver to rest in 0.35 s. How much force is exerted by the seat on the driver? Compute for the acceleration experienced by the driver during collision.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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![**Problem Statement:**
1. Suppose a car is involved in a collision in which it is brought to a constant speed of 31 m/s. Fortunately, the seat belt worn by the 65 kg driver brought the driver to rest in 0.35 s. How much force is exerted by the seat on the driver? Compute for the acceleration experienced by the driver during collision.
**Explanation:**
To solve this problem, we need to calculate the force exerted by the seat on the driver and the acceleration experienced by the driver during the collision.
**Given Data:**
- Initial speed of the car (\(v_i\)) = 31 m/s
- Final speed of the driver (\(v_f\)) = 0 m/s (since the driver comes to rest)
- Mass of the driver (\(m\)) = 65 kg
- Time (\(t\)) = 0.35 s
**Calculations:**
1. **Acceleration (\(a\)):**
Using the formula for acceleration:
\[
a = \frac{v_f - v_i}{t} = \frac{0 - 31 \, \text{m/s}}{0.35 \, \text{s}} = \frac{-31}{0.35} \, \text{m/s}^2
\]
Calculate \(a\).
2. **Force (\(F\)):**
Using Newton's second law:
\[
F = m \times a
\]
Substitute the values of \(m\) and \(a\) to find the force.
This problem is a practical application of Newton's laws of motion and provides insight into the importance of seat belts in reducing the impact force during collisions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdb15c522-e1e4-4c68-8ccc-3289f662fe75%2Fc25dfede-6454-454b-baf1-cb7262f43c5c%2Fxvtriz_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
1. Suppose a car is involved in a collision in which it is brought to a constant speed of 31 m/s. Fortunately, the seat belt worn by the 65 kg driver brought the driver to rest in 0.35 s. How much force is exerted by the seat on the driver? Compute for the acceleration experienced by the driver during collision.
**Explanation:**
To solve this problem, we need to calculate the force exerted by the seat on the driver and the acceleration experienced by the driver during the collision.
**Given Data:**
- Initial speed of the car (\(v_i\)) = 31 m/s
- Final speed of the driver (\(v_f\)) = 0 m/s (since the driver comes to rest)
- Mass of the driver (\(m\)) = 65 kg
- Time (\(t\)) = 0.35 s
**Calculations:**
1. **Acceleration (\(a\)):**
Using the formula for acceleration:
\[
a = \frac{v_f - v_i}{t} = \frac{0 - 31 \, \text{m/s}}{0.35 \, \text{s}} = \frac{-31}{0.35} \, \text{m/s}^2
\]
Calculate \(a\).
2. **Force (\(F\)):**
Using Newton's second law:
\[
F = m \times a
\]
Substitute the values of \(m\) and \(a\) to find the force.
This problem is a practical application of Newton's laws of motion and provides insight into the importance of seat belts in reducing the impact force during collisions.
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