C1. Sieve analysis data for two inorganic soils are provided in Table 1. Soil 1 has LL =60 and PL = 36. Soil 2 has LL = 23 and PL =15. To plot the particle size distributioncurves for Soils 1 and 2 using the attached sheet. Determine the effective grain size,D10 for Soil 2. Determine theUSCS designation for each soil.List step by step how you makeyour choices.Table 1. Sieve Analysis Data.MeshSieveNo.410204060100200opening(mm)4.7502.0000.8500.4250.2500.1500.075Soil 1% finer1001009893888377Soil 2% finer100906438292111% Finer12010080604020II11110T+4-I I JFTT I 1Bullie aller11 1TEEJ1 I 01: 1HI IF ++4 FTLLU1L114IIFT 7LI 1TTIT 11 31 11 1LIJ-LIT J {LILII 1 1rtII ITLIL11 JJFILI 31II1IB11TrT1CAJ<-+I1Particle Size Distribution1ITHE SEDETLIILLtFT4JII11 1 1Fr-r71JLeadL1ITIP ESI-11IETIParticle size (mm)IILL1 T E TTH0.1JJEIFLILIIF11 TJ II T1FIRE 1-I FFIEETTI 11LII IIFJF7+411 3 1 1FRLLIET7 TLI1 #11I1LE15J11I0.01

Sieve analysis data for two soils are given. We need to determine effective grain size D10 for soil…

1. Sieve analysis data for two inorganic soils are provided in Table 1. Soil 1 has LL = 60 and PL = 36. Soil 2 has LL = 23 and PL =15. To plot the particle size distribution curves for Soils 1 and 2 using the attached sheet. Determine the effective grain size, D10 for Soil 2. Determine the USCS designation for each soil. List step by step how you make your choices. Table 1. Sieve Analysis Data. Mesh Sieve No. 4 10 20 40 60 100 200 Soil 1 % finer opening (mm) 4.750 2.000 0.850 98 0.425 93 0.250 88 0.150 83 0.075 77 100 100 Soil 2 % finer 100 90 64 38 29 21 11 % Finer 120 100 80 60 40 20 0 10 Particle Size Distribution 1 0.1 Particle size (mm) 0.01

1. Sieve analysis data for two inorganic soils are provided in Table 1. Soil 1 has LL = 60 and PL = 36. Soil 2 has LL = 23 and PL =15. To plot the particle size distribution curves for Soils 1 and 2 using the attached sheet. Determine the effective grain size, D10 for Soil 2. Determine the USCS designation for each soil. List step by step how you make your choices. Table 1. Sieve Analysis Data. Mesh Sieve No. 4 10 20 40 60 100 200 Soil 1 % finer opening (mm) 4.750 2.000 0.850 98 0.425 93 0.250 88 0.150 83 0.075 77 100 100 Soil 2 % finer 100 90 64 38 29 21 11 % Finer 120 100 80 60 40 20 0 10 Particle Size Distribution 1 0.1 Particle size (mm) 0.01

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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SITUATION 9 The result of sieve analysis of three soils is given next. It is required to classify these soils according to the AASHTO Classification System. Use the attached AASHTO Classification of Highway Subgrade Materials Table. (a) Classification of Soil A. (b) Classification of Soil B. (c) Classification of Soil C. Sieve Analysis Results for Situation 9 Sieve Analysis Sieve Diameter, Percent Passing Number mm. 4.76 90 100 100 8. 2.38 84 90 100 10 2. 72 77 98 20 0.84 66 59 91 40 0.42 58 50 85 60 0.25 50 42 79 100 0.149 44 36 70 200 0.074 38 33 LL 42 46 47 PL 23 29 24 63
The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760 96 6 2.380 91 10 2.000 89 20 0.840 85 40 0.420 81 60 0.250 78 100 0.149 67 200 0.074 64 LL 40 PL 30 Determine its classification using USCS. ML MH None of the above CL CH
47.) The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760 89 6 2.380 70 10 2.000 63 20 0.840 55 40 0.420 31 60 0.250 20 100 0.149 18 200 0.074 4 LL 60 PL 40 Determine its classification using USCS. GW SP None of the above SW GP
Can I get a step by step for this question? Using the data presented for the given soil sample, determine the soil classification using the ASTM and the AASHTO Soil classification system. Give the group index if needed. The soil is inorganic soil. Sieve No. 19mm (¾ in.) 12.5mm (1/2in.) No. 4 (4.75 mm) No. 10 (2.00 mm) No. 20 (0.850 mm) No. 40 (0.425 mm) No. 100 (0.150 mm) No. 200 (0.075 mm) Percent Passing 100 95 63 50 44 37 28 22 Cu: 5.5 and Cc: 1.8 Atterberg limits: Liquid limit. 33%, Plasticity Index: 17%.
2. The following data were recorded during particle size analysis tests in the laboratory. Plot the grading curve and determine the grading characteristics. Using the information, classify the soil according to BSCS. Soil 1 Fine-Mesh dry sieve analysis data: Sieve Size 425 (mm or um) Mass 1.18 600 300 212 150 63 retained 1.9 3.2 8.1 10.4 22.7 126.1 (g) Total sample = 212.0 g
Question 44 The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 No. 8 No. 10 No. 20 4.760 96 2.380 80 2.000 78 0.840 61 No. 40 0.420 56 No. 60 0.250 48 No. 100 0.150 39 No. 200 0.075 33 Characteristics of No. 40 Fraction LL 45 PL 36 General classification Granular materials (35% or less of total sample passing No. 200) A-I A-2 Group classification A-l-a A-1-5 A3 A-24 A-25 A-2-6 A-2-7 Sieve analysis (percent passing) No. 10 No. 40 No. 200 50 max. 30 max. 15 max. 50 max. 25 max. 51 min. 10 max. 35 max. 35 max. 35 max. 35 max. Characteristics of fraction passing No. 40 Liquid limit Plasticity index 40 max. 41 min. 40 max. 41 min. 6 max. NP 10 max. 10 max. 11 min. 11 min. Usual types of significant Stone fragments, gravel, and sand Fine Silty or clayey gravel and sand sand
The result of sieve analysis of three soils is given next. It is required to classify these soils according to the AASHTO Classification System. Use the attached AASHTO Classification of Highway Subgrade Materials Table. (a) Classification of Soil A. (b) Classification of Soil B. (c) Classification of Soil C. Sieve Analysis Results for Situation 9 Sieve Analysis Sieve Diameter, Percent Passing Number mm. 4.76 90 100 100 8. 2.38 84 90 100 10 2. 72 77 98 20 0.84 66 59 91 40 0.42 58 50 85 60 0.25 50 42 79 100 0.149 44 36 70 200 0.074 38 33 LL 42 46 47 PL 23 29 24 63
Question 3: For an inorganic soil the following grain - size analysis is given. U.S sieve Percent analysis 4 passing 100 10 90 20 64 40 38 80 18 200 13 For this soil, LL=23 and Pl=19, classify the soil by using a. AASHTO b. USCS c. Give group name and group symbols
5. The following information is obtained from a sieve analysis to determine the range of particle sizes in a granular soil sample. Sieve Size Sieve Opening (4.76) Percent Finer#4 4.76 96#10 2.00 80#20 0.84 51#40 0.42 38#60 0.25 25#100 0.149 12#200 0.074 5 Present the information as grain-size curve on semi-logarithmic coordinates of percent finer against particle size diameter. From the plot, determine the uniformity coefficient Cu.
2.8 2.7 The following are the results of a sieve and hydrometer analysis. Sieve number/ grain size Analysis Sieve Hydrometer Analysis Sieve 40 80 170 200 0.04 mm 0.02 mm 0.01 mm 0.005 mm 0.0015 mm Hydrometer Sieve number/ grain size Percent finer than a. Draw the grain-size distribution curve. b. Determine the percentages of gravel, sand, silt, and clay according to the MIT system. c. Repeat Part b according to the USDA system. d. Repeat Part b according to the AASHTO system. Repeat Problem 2.7 with the following data: 20 30 40 60 80 200 0.05 mm 0.03 mm 0.015 mm 0.006 mm 0.004 mm 0.0015 mm 100 96 85 80 59 39 26 15 8 Cengage Learning 2014 Percent finer than 100 96 90 76 65 34 27 19 11 7 6 5 Ⓒ Cengage Learning 2014
Sr B. ( A Soil Specimen has the following characteristics: % passing No.4 sieve = 85 % passing No.200 sieve = 11 D60 = 2 mm D30=0.35 mm D₁0 = 70 μm D8=2 μm L.L = 36% P.L = 31% 1. Classify the specimen according to the Unified Soil Classification System (USCS). Assign the group name and the group symbol. 2. Determine the soil activity. 3. Determine the soil Liquidity index and consistency index if wc = 26%.
• Particle size analyses were carried out on two soils-Soil A and Soil B-and the particle size distribution curves are shown in Figure % Finer Clay 100 90 80 70 60 50 40 30 20 10 0 0.001 + Silt Soil A Sand Soil B 0.01 0.1 1 Particle size (mm) - log scale Gravel 10 Soil A B 1. Classify these soils according to USCS and ASTM-CS 2. Is either of the soils organic? LL 26 (oven-dried; assume same for not dried) Nonplastic PL 18