1. Show how the forward and reverse reaction rates respond to a sudden increase in the volume of the system at t1. Use a solid line for the forward rate and a dotted line for the reverse rate. The system restores equilibrium at t2. The arrow diagram on the right is another way of depicting the same information. You may use it to do your rough work. You may use the graph provided or paste one. N2O4(g) ⇌ 2 NO2 (g)
1. Show how the forward and reverse reaction rates respond to a sudden increase in the volume of the system at t1. Use a solid line for the forward rate and a dotted line for the reverse rate. The system restores equilibrium at t2. The arrow diagram on the right is another way of depicting the same information. You may use it to do your rough work. You may use the graph provided or paste one.
N2O4(g) ⇌ 2 NO2 (g)
2. The solubility of a substance is its highest possible concentration at a given temperature. Any further solid added to the solution will remain undissolved in equilibrium with the dissolved state. Dissolving sodium sulphate in water is exothermic.
Na2SO4(s) ⇌ 2 Na+ (aq) + SO42- (aq) + heat
State whether sodium sulfate will be less soluble or more soluble when the temperature of the solution is increased. Explain.
3. Complete the following plots. The system below is at equilibrium prior to t1. The system is suddenly cooled at t1. The system responds to this stress between t and t2 until it re-equilibrates at t2. You may use this graph of paste one.
N2O4(g) + 57 kJ ⇌ 2 NO2(g)
![1.2
1.0
[NO,]
0.8
0.6
[N,O4] 0.4
0.2
0.0
t,
t2
Time](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fafdd7b46-d357-400a-bdf2-b638efb53d17%2Fdcd10354-fe59-4d3b-b3a6-b22ad38fb3ac%2Fz8h3flq_processed.png&w=3840&q=75)
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