1. Rhonda is competing on a game show. First she randomly decides on a target of 1 or 2 and chooses card A or B. Then she spins the spinner on the other side of the card. Front Back Front Back A B 2 a. What is P(1) if Rhonda chooses spinner A? P(11A)% = %3D b. What is P(1) if Rhonda chooses spinner B? P(11B) = C. Choose the correct symbol to make the statement true. Events A and B are dependent because P(1|B) ( =, #) P(11A)
1. Rhonda is competing on a game show. First she randomly decides on a target of 1 or 2 and chooses card A or B. Then she spins the spinner on the other side of the card. Front Back Front Back A B 2 a. What is P(1) if Rhonda chooses spinner A? P(11A)% = %3D b. What is P(1) if Rhonda chooses spinner B? P(11B) = C. Choose the correct symbol to make the statement true. Events A and B are dependent because P(1|B) ( =, #) P(11A)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
Related questions
Topic Video
Question
What’s the answer for A1, A2 and A3? Plz help me

Transcribed Image Text:### Conditional Probability
1. **Rhonda is competing on a game show.** First, she randomly decides on a target of 1 or 2 and chooses card A or B. Then she spins the spinner on the other side of the card.
Here are the details of the cards as shown:
**Front side of cards:**
- Card A: Plain with no markings.
- Card B: Plain with no markings.
**Back side of cards with spinners:**
- Card A:
- 1
- 2
- Card B:
- 1
- 2
- 1
- 1
**Questions:**
a. What is \( P(1) \) if Rhonda chooses spinner A? \( P(1|A) = \) ______
b. What is \( P(1) \) if Rhonda chooses spinner B? \( P(1|B) = \) ______
c. Choose the correct symbol to make the statement true.
Events A and B are dependent because \( P(1|B) \) ( = , ≠ ) \( P(1|A) \)
2. **In a survey, half of the students walk to school and the other half take the bus.** Of the students who take the bus to school, 40% play sports. Complete the tree diagram and the calculation to find the probability below.
**Tree Diagram Explanation:**
The tree diagram provided indicates the following probabilities:
- The probability of walking to school: \( 0.5 \)
- The probability of taking the bus: \( 0.5 \)
If the student walks to school:
- Probability of playing sports: \( 0.35 \)
- Probability of not playing sports: \( 0.65 \)
If the student takes the bus:
- Probability of playing sports: \( 0.40 \)
- Probability of not playing sports: \( 0.60 \)
**Calculation:**
\( P(\text{plays sports and takes bus}) = P(\text{sports}\ |\ \text{bus}) \cdot P(\text{______}) \)
\( = 0.40 \cdot (\text{______}) \)
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 3 steps

Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, probability and related others by exploring similar questions and additional content below.Recommended textbooks for you

A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON


A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON
