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1. Rhonda is competing on a game show. First she randomly decides on a target of 1 or 2 and chooses card A or B. Then she spins the spinner on the other side of the card. Front Back Front Back A B 2 a. What is P(1) if Rhonda chooses spinner A? P(11A)% = %3D b. What is P(1) if Rhonda chooses spinner B? P(11B) = C. Choose the correct symbol to make the statement true. Events A and B are dependent because P(1|B) ( =, #) P(11A)

1. Rhonda is competing on a game show. First she randomly decides on a target of 1 or 2 and chooses card A or B. Then she spins the spinner on the other side of the card. Front Back Front Back A B 2 a. What is P(1) if Rhonda chooses spinner A? P(11A)% = %3D b. What is P(1) if Rhonda chooses spinner B? P(11B) = C. Choose the correct symbol to make the statement true. Events A and B are dependent because P(1|B) ( =, #) P(11A)

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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What’s the answer for A1, A2 and A3? Plz help me
### Conditional Probability 1. **Rhonda is competing on a game show.** First, she randomly decides on a target of 1 or 2 and chooses card A or B. Then she spins the spinner on the other side of the card. Here are the details of the cards as shown: **Front side of cards:** - Card A: Plain with no markings. - Card B: Plain with no markings. **Back side of cards with spinners:** - Card A: - 1 - 2 - Card B: - 1 - 2 - 1 - 1 **Questions:** a. What is \( P(1) \) if Rhonda chooses spinner A? \( P(1|A) = \) ______ b. What is \( P(1) \) if Rhonda chooses spinner B? \( P(1|B) = \) ______ c. Choose the correct symbol to make the statement true. Events A and B are dependent because \( P(1|B) \) ( = , ≠ ) \( P(1|A) \) 2. **In a survey, half of the students walk to school and the other half take the bus.** Of the students who take the bus to school, 40% play sports. Complete the tree diagram and the calculation to find the probability below. **Tree Diagram Explanation:** The tree diagram provided indicates the following probabilities: - The probability of walking to school: \( 0.5 \) - The probability of taking the bus: \( 0.5 \) If the student walks to school: - Probability of playing sports: \( 0.35 \) - Probability of not playing sports: \( 0.65 \) If the student takes the bus: - Probability of playing sports: \( 0.40 \) - Probability of not playing sports: \( 0.60 \) **Calculation:** \( P(\text{plays sports and takes bus}) = P(\text{sports}\ |\ \text{bus}) \cdot P(\text{______}) \) \( = 0.40 \cdot (\text{______}) \)
Transcribed Image Text:### Conditional Probability 1. **Rhonda is competing on a game show.** First, she randomly decides on a target of 1 or 2 and chooses card A or B. Then she spins the spinner on the other side of the card. Here are the details of the cards as shown: **Front side of cards:** - Card A: Plain with no markings. - Card B: Plain with no markings. **Back side of cards with spinners:** - Card A: - 1 - 2 - Card B: - 1 - 2 - 1 - 1 **Questions:** a. What is \( P(1) \) if Rhonda chooses spinner A? \( P(1|A) = \) ______ b. What is \( P(1) \) if Rhonda chooses spinner B? \( P(1|B) = \) ______ c. Choose the correct symbol to make the statement true. Events A and B are dependent because \( P(1|B) \) ( = , ≠ ) \( P(1|A) \) 2. **In a survey, half of the students walk to school and the other half take the bus.** Of the students who take the bus to school, 40% play sports. Complete the tree diagram and the calculation to find the probability below. **Tree Diagram Explanation:** The tree diagram provided indicates the following probabilities: - The probability of walking to school: \( 0.5 \) - The probability of taking the bus: \( 0.5 \) If the student walks to school: - Probability of playing sports: \( 0.35 \) - Probability of not playing sports: \( 0.65 \) If the student takes the bus: - Probability of playing sports: \( 0.40 \) - Probability of not playing sports: \( 0.60 \) **Calculation:** \( P(\text{plays sports and takes bus}) = P(\text{sports}\ |\ \text{bus}) \cdot P(\text{______}) \) \( = 0.40 \cdot (\text{______}) \)
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