1. Repeat Example 4.2, parts (a) and (b), assuming a three-phase 34.5 kV wye-grounded feeder main that has 350 kcmil 19-strand copper conductors with an equivalent spacing of 37 in between phase conductors and a lagging-load power factor of 0.9.  K=3.5935 ×10-5 [%VD/KVA-mi] Below attached image is for example 4.2

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1. Repeat Example 4.2, parts (a) and (b), assuming a three-phase 34.5 kV wye-grounded feeder main that has 350 kcmil 19-strand copper conductors with an equivalent spacing of 37 in between phase conductors and a lagging-load power factor of 0.9.  K=3.5935 ×10-5 [%VD/KVA-mi]

Below attached image is for example 4.2

 

from Table A-1 for 50°C and 60 Hz
Example 4-2 Assume that the feeder shown in Fig. 4-22 has the same charac-
from Table A-10 for 60 Hz and 37-inch spacing
SOLUTION
(r cos 0 + x sin 0)G x 1000)
V,V.
(a) From Eq. (4-77),
pu v
NL = , + x, = 0.7456 2/mi
X, = 0.609 Q mi
X = 0.1366 /mi
cos 0 = 0.9, lagging
V = V, = 2400 V, line-to-neutral voltage
where r = 1.503 /mi
from Table A-1 for 60 Hz
Therefore the per unit voltage drop per kilovoltampere-mile i
(1.503 x 0.9 + 0.7456 x 0.4359)G x 1000
24002
2 0.0001 VD/(k VA mi)
or
K= 0.01 % VD/(k VA mi)
(b) From Fig. 4-17, the K constant for #4 copper conductors is
K = 0.01 % VD/(kVA mi)
which is the same as the one found in part a.
teristics as the one in Example 4-1 and a lumped-sum load of 500 kVA wi.
lagging-load power factor of 0.9 is connected at the end of a l-mi-long feed
main. Calculate the percent voltage drop in the main.
SOLUTION The percent voltage drop in the main is
% VD = x K x S,
= 1.0 mi x 0.01% VD/(kVA · mi) x 500 kVA
= 5.0%
S= = 1 mi
# 4 copper
D = 37
AVLL = 4.16 kV
500 kVA
PF = 0.9 lag
Figure 4-22
Transcribed Image Text:from Table A-1 for 50°C and 60 Hz Example 4-2 Assume that the feeder shown in Fig. 4-22 has the same charac- from Table A-10 for 60 Hz and 37-inch spacing SOLUTION (r cos 0 + x sin 0)G x 1000) V,V. (a) From Eq. (4-77), pu v NL = , + x, = 0.7456 2/mi X, = 0.609 Q mi X = 0.1366 /mi cos 0 = 0.9, lagging V = V, = 2400 V, line-to-neutral voltage where r = 1.503 /mi from Table A-1 for 60 Hz Therefore the per unit voltage drop per kilovoltampere-mile i (1.503 x 0.9 + 0.7456 x 0.4359)G x 1000 24002 2 0.0001 VD/(k VA mi) or K= 0.01 % VD/(k VA mi) (b) From Fig. 4-17, the K constant for #4 copper conductors is K = 0.01 % VD/(kVA mi) which is the same as the one found in part a. teristics as the one in Example 4-1 and a lumped-sum load of 500 kVA wi. lagging-load power factor of 0.9 is connected at the end of a l-mi-long feed main. Calculate the percent voltage drop in the main. SOLUTION The percent voltage drop in the main is % VD = x K x S, = 1.0 mi x 0.01% VD/(kVA · mi) x 500 kVA = 5.0% S= = 1 mi # 4 copper D = 37 AVLL = 4.16 kV 500 kVA PF = 0.9 lag Figure 4-22
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