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1. Recalculate the case below using SI

1. Recalculate the case below using SI

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Hello good evening Sir,
Permission, i have a question in my homework. The following bellow is question. Please advice. Thank you

Regards,
Irfan

1. Recalculate the case below using SI

2. What if the mercury fluid is replaced with kerosene, what is the pressure?

 

Energy conservation(cont.) If energy is added, removed or lost via pumps turbines, friction, etc.then we use Pi Extended Bernoulli's Equation +z, +h4-h; -h, 2g P2, V + Z2 2g Example: Determine the efficiency of the pump if the power input of the motor is measured to be 1.5 hp. It is known that the pump delivers 300 gal/min of water. No turbine work and frictional losses, hence: h=h=0. Also z,=Z, 4-in dia.pipe Given: Q=300 gal/min=0.667 ft/s=AV V= Q/A,=3.33 ft/s V,-Q/A,=7.54 ft/s 6-in dia. pipe 1 kinetic energy head gain +. pump V} – V (7.54) – (3.33)² = 0.71ft, Z=15 in 2g 2*32.2 Looking at the pressure term: P +7 „7, +Y „z = P2 +Y „Z, +Y wZ m Mercury (y-844.9 lb/ft*) water (y-62.4 lb/ft3) P2 - P = (7 m -Y „)z 1 hp=550 lb-ft/s = (844.9 – 62.4)*1.25 = 978.13 lb/ ft?
Transcribed Image Text:Energy conservation(cont.) If energy is added, removed or lost via pumps turbines, friction, etc.then we use Pi Extended Bernoulli's Equation +z, +h4-h; -h, 2g P2, V + Z2 2g Example: Determine the efficiency of the pump if the power input of the motor is measured to be 1.5 hp. It is known that the pump delivers 300 gal/min of water. No turbine work and frictional losses, hence: h=h=0. Also z,=Z, 4-in dia.pipe Given: Q=300 gal/min=0.667 ft/s=AV V= Q/A,=3.33 ft/s V,-Q/A,=7.54 ft/s 6-in dia. pipe 1 kinetic energy head gain +. pump V} – V (7.54) – (3.33)² = 0.71ft, Z=15 in 2g 2*32.2 Looking at the pressure term: P +7 „7, +Y „z = P2 +Y „Z, +Y wZ m Mercury (y-844.9 lb/ft*) water (y-62.4 lb/ft3) P2 - P = (7 m -Y „)z 1 hp=550 lb-ft/s = (844.9 – 62.4)*1.25 = 978.13 lb/ ft?
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