Kerosene has an API gravity of 42.5. What is the specific gravity of kerosene at 16°C? How does this compare with the value in Table 2.7? What is the energy density (MJ/L) of kerosene at 16°C? Use the data given in Table 2.7. TABLE 2.7Typical Properties of Fuel OilsFuel Grade No.PropertyColorSpecific gravity at 16°CKinematic viscosity at 38°C (m²/s)Pour point (°C)Flash point (°C)Autoignition temp. (°C)Carbon (wt%)Carbon residue (wt%)Hydrogen (wt %)Oxygen (wt%)Ash (wt%)HHV (MJ/kg)1KeroseneClear0.8251.6 x 10-6<-173823086.5Trace13.20.0146.22DistillateAmber0.8652.6 x 10-6<-183826086.4Trace12.70.04<0.0145.44VeryLightResidualBlack0.92815 x 10-6-235526386.12.511.90.270.0243.85LightResidualBlack0.95350 x 10-6-155-85.55.011.70.30.0343.26ResidualBlack0.986360 x 10-6196640885.712.010.50.38 0.640.0442.4

Answered: Image /qna-images/answer/c5a21458-04c6-46b5-9d0b-b7f47949d071.jpg

Answered: Kerosene has an API gravity of 42.5.…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Concept explainers

Question

Kerosene has an API gravity of 42.5. What is the specific gravity of kerosene at 16°C? How does this compare with the value in Table 2.7? What is the energy density (MJ/L) of kerosene at 16°C? Use the data given in Table 2.7.

TABLE 2.7
Typical Properties of Fuel Oils
Fuel Grade No.
Property
Color
Specific gravity at 16°C
Kinematic viscosity at 38°C (m²/s)
Pour point (°C)
Flash point (°C)
Autoignition temp. (°C)
Carbon (wt%)
Carbon residue (wt%)
Hydrogen (wt %)
Oxygen (wt%)
Ash (wt%)
HHV (MJ/kg)
1
Kerosene
Clear
0.825
1.6 x 10-6
<-17
38
230
86.5
Trace
13.2
0.01
46.2
2
Distillate
Amber
0.865
2.6 x 10-6
<-18
38
260
86.4
Trace
12.7
0.04
<0.01
45.4
4
Very
Light
Residual
Black
0.928
15 x 10-6
-23
55
263
86.1
2.5
11.9
0.27
0.02
43.8
5
Light
Residual
Black
0.953
50 x 10-6
-1
55
-
85.5
5.0
11.7
0.3
0.03
43.2
6
Residual
Black
0.986
360 x 10-6
19
66
408
85.7
12.0
10.5
0.38 0.64
0.04
42.4

Expert Solution

Step by step

Solved in 3 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions