1. Reaction of Br₂ with 1-hexene. سلم 3. Reaction of Br₂ with 2-methyl-2-pentene. 2. Reaction of Br₂ with 2-methyl-1-pentene. Incorrect Br 4. Reaction of Br₂ with (Z)-3-hexene. Clearly show stereochemistry by drawing one wedge bond, one hashed bond and two in-plane bonds.

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Give the expected major product from the reaction of five alkenes with Br2Br2. The starting materials have been drawn for you. Amend the structures to show the major organic product. Show chirality where indicated and only draw one enantiomer if more than one is possible. Include hydrogen atoms on chirality centers.

**1. Reaction of Br₂ with 1-hexene.**

The diagram shows the product of the reaction between bromine (Br₂) and 1-hexene. In this reaction, the double bond in 1-hexene undergoes an addition reaction with Br₂, resulting in the formation of a dibromo compound. The structure depicted consists of a hexane chain where two bromine atoms are attached to the former double-bonded carbons.

**2. Reaction of Br₂ with 2-methyl-1-pentene.**

This diagram illustrates the product of the reaction between bromine and 2-methyl-1-pentene. The double bond is replaced by two single bonds with bromine atoms, resulting in the formation of a dibromo compound. The structure shows the methyl group on the second carbon of the main chain.

**3. Reaction of Br₂ with 2-methyl-2-pentene.**

The diagram depicts the result of adding bromine to 2-methyl-2-pentene. The reaction involves the addition of bromine across the double bond, forming a dibromo alkane. The product includes a substituted pentane backbone with bromine atoms replacing the original double bond.

**4. Reaction of Br₂ with (Z)-3-hexene.**

For the reaction with (Z)-3-hexene, the stereochemistry is crucial. This reaction involves the addition of Br₂ across the double bond. The instructions specify to show stereochemistry by drawing one wedge bond (indicating a bond coming out of the plane), one hashed bond (indicating a bond going behind the plane), and two in-plane bonds. This clearly illustrates the 3D configuration of the resulting dibromo compound, maintaining the original geometric orientation of the (Z) isomer.
Transcribed Image Text:**1. Reaction of Br₂ with 1-hexene.** The diagram shows the product of the reaction between bromine (Br₂) and 1-hexene. In this reaction, the double bond in 1-hexene undergoes an addition reaction with Br₂, resulting in the formation of a dibromo compound. The structure depicted consists of a hexane chain where two bromine atoms are attached to the former double-bonded carbons. **2. Reaction of Br₂ with 2-methyl-1-pentene.** This diagram illustrates the product of the reaction between bromine and 2-methyl-1-pentene. The double bond is replaced by two single bonds with bromine atoms, resulting in the formation of a dibromo compound. The structure shows the methyl group on the second carbon of the main chain. **3. Reaction of Br₂ with 2-methyl-2-pentene.** The diagram depicts the result of adding bromine to 2-methyl-2-pentene. The reaction involves the addition of bromine across the double bond, forming a dibromo alkane. The product includes a substituted pentane backbone with bromine atoms replacing the original double bond. **4. Reaction of Br₂ with (Z)-3-hexene.** For the reaction with (Z)-3-hexene, the stereochemistry is crucial. This reaction involves the addition of Br₂ across the double bond. The instructions specify to show stereochemistry by drawing one wedge bond (indicating a bond coming out of the plane), one hashed bond (indicating a bond going behind the plane), and two in-plane bonds. This clearly illustrates the 3D configuration of the resulting dibromo compound, maintaining the original geometric orientation of the (Z) isomer.
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