1. Prove the following Equations:a. y' = Ydry + Yw (n – 1)Vw(Ysat-Ydry)Vw(Ydry-Ysat)+Wwb. e =Note:y'= Submerge unit weightYan- Dry unit weightYou unit weight of watern= Porositye= Void RatioYsat= Saturated unit weightV= Volume of waterW= Weight of waterTopic: Weight- Volume Relationship (Soil Mechanics)

Answered: Image /qna-images/answer/c7964a59-a101-4331-b2f5-3acf93d9045e.jpg

Answered: 1. Prove the following Equations: a. y'…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Reynold' number is used to determine the type of flow pattern through a pipe. It is defined by the equation where p=density.u=viscosity. V=velocity, D = dilameter of pipe, Perform a detailed UNIT ANALYSIS to determine the unit of Reynold's number State your answer in a complete statement.
A. Explain how you can obtain the volume of an irregular solid insoluble in water. B. How can you obtain the weight of an equal volume of water ?
Subject: Mechanics of Fluids Please include complete units of measurement. Show complete solutions. Write legibly Choose the answer below.
Compute ‘h’. Neglect the box type figure for the hydrometer as it is just used as weights of hydrometer to submerge itself in fluid.
5 FLUID MECHANICS: Write Legibly and Show complete solutions. Include complete units in the solutions
1 FLUID MECHANICS: Write Legibly and Show complete solutions. Include complete units in the solutions
Solve and show solutions. Figure 01 below. (Subject: Fluid Mechanics)
Subject: Mechanics of Fluids Please include complete units of measurement. Show complete solutions. Write legibly Choose the answer below.
Find the pressure in the water tank shown in Figure 1. TABLE C1 Areas Rectangle Triangle Circle C. PROPERTIES OF AREAS AND VOLUMES Semicircle Ellipse Semiellipse Sketch Ti b TE b+d b 400 Water 砰 2a T 42 2b Area bh bh/2 TD² 14 S = 1.60 Figure 1: Water pipe schematic layout. #D²18 4 cm mab 7 cm mab/2 S=0.75 10 cm Centroid y = h/2 y-h/3 y=r ỳ Arist y=b cm ỹ=4b/3m Hg Second moment I = bh²³/12 Īxy = 0 I=bk²/36 Ixy = (b-2d)bh³/72 Ï = #D*/64 1,- #D¹/128 Ī= mab³/4 1,= mab³/8
I would like to ask if how did you get 40 in step 8 as the volume in the solution?
IV. CALCULATION 1. Calculate the absolute viscosity (u) as follows: 1 [d2 - (p. – p1) · g] 18 = diameter of sphere P. = density of sphere pr = density of fluid Where: d gravitational acceleration, 9.81 m/s? terminal velocity, D/t VT =
Specific Gravity =(W_(S))/((W_(SSD)-W_("submerged "))) Explain how (W_(SSD)-W_("submerged ")) represents the "weight of an equal volume of water".

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