1. Prove that if we colour the edges of K5 with 2 colours, red and green, so that the number of red edges is not equal to the number of green edges, then K5 will always have a monochromatic triangle.
1. Prove that if we colour the edges of K5 with 2 colours, red and green, so that the number of red edges is not equal to the number of green edges, then K5 will always have a monochromatic triangle.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:1. Prove that if we colour the edges of K5 with 2 colours, red and green, so that the number of
red edges is not equal to the number of green edges, then K5 will always have a
monochromatic triangle.
2. We colour the edges of the graph K₁6 using 3 colours, red, green, and blue. Prove that if the
number of red, green, and blue edges are not all equal, then we will always have a
monochromatic triangle.
Hint: First show that if r, g, and b are not all equal, then there must be a vertex of K16 with at
least 6 edges of the same colour.
Expert Solution

Step 1: To prove this, let's proceed by
According to the question,contradiction. Suppose you color the edges of (the complete graph on 5 vertices) with 2 colors, red and green, in such a way that the number of red edges is not equal to the number of green edges, and there is no monochromatic triangle.
Let's choose a vertex
in
. Since
is a complete graph,
is connected to 4 other vertices by 4 edges.
Without loss of generality, assume there are more red edges than green edges in the graph. Then there are three possibilities for the edges coming out of
:
- 4 red and 0 green
- 3 red and 1 green
- 2 red and 2 green
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