1. Prove that a graph is bipartite if and only if it doesn't have any simple circuits of odd order. Hint. Use the fact that a graph is bipartite if and only if it is 2-colorable.
1. Prove that a graph is bipartite if and only if it doesn't have any simple circuits of odd order. Hint. Use the fact that a graph is bipartite if and only if it is 2-colorable.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Discrete math need some answers

Transcribed Image Text:1. Prove that a graph is bipartite if and only if it doesn't have any simple circuits of odd
order.
Hint. Use the fact that a graph is bipartite if and only if it is 2-colorable.
2. Are the two graphs in Figure 1 isomorphic? How about the graphs in Figure 2? or in
Figure 3? Prove your answers.
Figure 1: The first two graphs of Question 2
Figure 2: The middle two graphs of Question 2
3. Are the graphs in Figure 4 isomorphic? Prove your answer.
4. How many cut vertices does the path P, has for n 2 1?
Figure 3: The last two graphs of Question 2
E
H
10
Figure 4: The two graphs of Question 3

Transcribed Image Text:E
H
10
Figure 4: The two graphs of Question 3
Page 2
5. Show that the following graphs have no cut vertices:
(a) Cn for n > 3.
(b) Wn for n > 3.
(c) Qn for n > 1.
6. For which values of m and n does the complete bipartite graph Km,n have cut vertices?
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