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1. Phasor: Convert the following voltage and current signals into phasor (both rectangular and polar Forms) a) v(t) = 100 cos(wt + 30°) V b) i(t) = 5V2 cos(wt - 45°) V c) v(t) = 100 cos(wt – 45°) + 100 cos(wt) A d) i(t) = 5v2 cos(@t + 45°) + 5V2 cos(@t + 15°) A

1. Phasor: Convert the following voltage and current signals into phasor (both rectangular and polar Forms) a) v(t) = 100 cos(wt + 30°) V b) i(t) = 5V2 cos(wt - 45°) V c) v(t) = 100 cos(wt – 45°) + 100 cos(wt) A d) i(t) = 5v2 cos(@t + 45°) + 5V2 cos(@t + 15°) A

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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1. Phasor: Convert the following voltage and current signals into phasor (both rectangular and polar forms) a) v(t) = 100 cos(at + 30°) V b) i(t) = 5v2 cos(wt - 45°) V c) v(t) = 100 cos(@t - 45°) + 100 cos(@t) A d) i(t) = 5/2 cos(wt + 45°) + 5V2 cos(@t + 15°) A %3D %3D
Transcribed Image Text:1. Phasor: Convert the following voltage and current signals into phasor (both rectangular and polar forms) a) v(t) = 100 cos(at + 30°) V b) i(t) = 5v2 cos(wt - 45°) V c) v(t) = 100 cos(@t - 45°) + 100 cos(@t) A d) i(t) = 5/2 cos(wt + 45°) + 5V2 cos(@t + 15°) A %3D %3D
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