1. Passengers in the jet transport A flying east at a speed of 800 km/h observe a second jet plane B that passes under the transport in horizontal flight. Although the nose of B is pointed in the 45° northeast direction, plane B appears to the passengers in A to be moving away from the transport at the 60° angle as shown. Determine the true velocity of B. -5800KM For √₂ = ? √3/A= ? *HISSIGNMENT: LISE TUO MORE METHODS/ SOLVING TECH. FOR THIS PROBLEM 145 sin (75) VBIA= Ival X 6-180-60-15 x= 75° VI/H sin 45 VELA Go" JA- Bookm/hr Visin45 Sin 15 1585.64 km/br ve Sin (75) = sin 60 VB/A Sin 45 VA sin 60 Booths in 60 Sin 75 S'il 75 V=717.26 km/h
1. Passengers in the jet transport A flying east at a speed of 800 km/h observe a second jet plane B that passes under the transport in horizontal flight. Although the nose of B is pointed in the 45° northeast direction, plane B appears to the passengers in A to be moving away from the transport at the 60° angle as shown. Determine the true velocity of B. -5800KM For √₂ = ? √3/A= ? *HISSIGNMENT: LISE TUO MORE METHODS/ SOLVING TECH. FOR THIS PROBLEM 145 sin (75) VBIA= Ival X 6-180-60-15 x= 75° VI/H sin 45 VELA Go" JA- Bookm/hr Visin45 Sin 15 1585.64 km/br ve Sin (75) = sin 60 VB/A Sin 45 VA sin 60 Booths in 60 Sin 75 S'il 75 V=717.26 km/h
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Please solve these with 2 more methods thank you! Don't use the method in the sample solution provided.
(Answer will be same)
Handwritten Please

Transcribed Image Text:Relative Motion
1. Passengers in the jet transport A flying east at a speed of 800 km/h observe a second jet plane B that passes under the transport in horizontal
flight. Although the nose of B is pointed in the 45° northeast direction, plane B appears to the passengers in A to be moving away from the
transport at the 60° angle as shown. Determine the true velocity of B.
60⁰
-5800KM
Fr
VB/A
*HISSIGNMENT :
бие тшо море метная
SOLVING TECH. FOR THIS PROBLEM
145
VB
Ve
sin(75)
x
7°
VOLA
6-180-600-115
2x = 75
sin 45
VR/A
Ja=800km/hr
Go"
Vash45
Sin
VG/A=585.64 km/br
(
Sinc
Sin 60"
VESIA
Sin 45
VA sin 60 Booths in 60
S'il 75
Sin 75
√₂2₂=717.26km/125
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