1. On the incomplete ray diagram for an object in front of a curved mirror, trace the path of Ray 1 as you would do to find the location and size of the image. Flabels the focal point of the mirror. Add at least one other Ray to locate the image produced by this mirror. Identify whether this will form a real or virtual image. swer. Ray 1 Object Principal axis
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- Modified true or false. Write True if the statement is true. If not, write False and change the underlined word/s to make the statement correct. 4. You stand 1.0 m in front of a plane mirror. Your image is 1.0 m from you. 5. A plane mirror produces an image that is always of the same size as the object. 6. A concave mirror has a radius of curvature of 12 cm. Its focal length is 6.0 cm.Ray Diagrams - Convex Mirror A certain convex, spherical mirror has a focal length of 82.0 cm. If the object is 47 cm high and is situated 140 cm in front of the concave mirror, determine the following using the mirror and magnification equations: (a) Image distance (b) Magnification of the image (c) Is the image real or virtual, upright or inverted, larger or smaller. (d) Sketch the Ray diagram.1. Reflection - Plane (Flat) Mirror An object is place in front of a simple plane mirror, as shown. A. Please draw the reflection image of this object. B. Please label the object distance. C. Please label the image distance. ↑ Flat mirror do = -di. Ingriber modaten of work by K. Skills: Plane Mirror: Using Reflection Symmetry to Draw Image d Figure 2.2 Two you certes cnobot crafted by a favor the overcobaves Thoreys creed by using the bow of Cardighectada acivard, they seem to come from point G behind the mic which is where the inal mags in ocend. Testing this processo por m ind
- For the following lens, locate the image by drawing a ray diagram (3 rays) and describe the image as (inverted or upright, real or virtual, magnified or reduced). Converging lens a. Upright, virtual, reduced b. Inverted, real, magnified c. Inverted, virtual, magnified d. Upright, real, reduced1.)The diverging lens of the figure produces an image of an object to the left of the lens and 5.00 cm away from the center of the lens. The refracting index of the lens is 1.50. The magnitude of the focal length of the lens is 12.0 cm and the radius of curvature R1 is 15.0 cm. A.) Calculate the radius of curvature R2 of the lens. Show your work. B.) Fill in the following table with the focal length of the lens, the distance of the image and the distance of the object (you have to calculate that) with the correct signs! f s s' C.) Is the object to the left or to the right of the lens? (Select one.) D.) Is the image formed by the lens upright or inverted compared to the object? (Select one.)When considering the location of images formed by lenses, we often like to employ ray tracing diagrams. To do this we draw three rays of light and see where they intersect. 1. A ray parallel to the axis refracts through the far focal point. 2. A ray that enters the lens along a line through the near focal point emerges parallel to the axis. 3. A ray through the center of the lens does not bend. This method was shown to you in class for the following situation: An object and converging lenses with the distance to the object being greater than the focal length, do > f. object focal point do focal point Now you will complete the ray tracing diagram for an object that is closer than the focal length: de focal point image Answer the following based on your ray tracing: (a) Is the image real or virtual? (b) is the image larger or smaller than the object? focal point
- An object is placed 7.7 cm in front of a concave mirror of radius of curvature 10-cm. 1) Calculate the image distance. Follow the sign convention. (Express your answer to two significant figures). 2) Calculate the magnification of the image. (Express your answer to two significant figures). 3) Is the image real or virtual? 4) Is the image upright or inverted?1. Draw the ray diagrams for light coming from the object shown and passing through the converging lens to find where the image will be. 2. Is the image upright or inverted?Direction: Identify if the statement is a concave or convex mirroriens 1 Also called as a diverging lens 2. Reflective surface bulges towards the light source. 3. Also called as a converging mirror 4. The parallel light rays intersect at a focal point after reflection 5 Reflective surface bulges away from the light source 6. Positive focal length of a mirror 7. Lens with a thicker center 8. A lens that forms upright and reduced images. 9 A thinner center lens. 10. Lens that forms real and virtual images. 11. Converging lens is also known as. 12. Lens with a thinner edges. 13. Lens with a thicker edges. 14. Image located behind the mirror 15. Mirror with an inverted image. 16. q + of the lens 17. Negative focal length of the mirror 18. h'- of the mirror 19. h'+ of the lens 20. q- of the mirror 21. A mirror which is very dependent of the object positions. 22. Lens that can always produce a virtual image. 23. Mirror that is always upright. 24. Lens with the image formation on the object…
- 1. The diagram below shows two light rays emanating from the top of the object and incident towards the mirror. Describe how the reflected rays for these light rays can be drawn without actually using a protractor and the law of reflection.5. Use the image to the right to answer this question. If the total angle normal between the incident and reflected ray is 80", what is the angle of reflection (r)? incident ray reflected ray a. 0* b. 40° c. 80° d. 160° mirrorRadius of curvature of a converging lens is 80 cm. If an object of height 10 cm is placed at a distance of 20 cm from lens on the principal axis, find : a. image distance b. image height c. Draw ray diagram