1. NAOME,a.TsOOTsH3C2. КОН3. Нао", д1. LDA2. NBSb.H3C.*CH3ČH3с.H3C,H*, Br2`CH3CH3d.H3C.`CH3D30*ČH3D..е.1. LDA2. NCSH3CT CH3ČH3f.1. Mel„CH32. D30*

Here we have write the major product formed in the following reactions.

1. NaOMe, а. CH3 TsO OTs H3C 2. КОН 3. Hзо", д 1. LDA 2. NBS b. H3C, *CH3 ČH3 с. H*, Br2 H3C, CH3 CH3 d. H3C, CH3 D30* ČH3 D., е. 1. LDA 2. NCS H3C CH3 ČH3 f. 1. Mel .CH3 2. D30*

1. NaOMe, а. CH3 TsO OTs H3C 2. КОН 3. Hзо", д 1. LDA 2. NBS b. H3C, CH3 ČH3 с. H, Br2 H3C, CH3 CH3 d. H3C, CH3 D30* ČH3 D., е. 1. LDA 2. NCS H3C CH3 ČH3 f. 1. Mel .CH3 2. D30*

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Applications of Molecular Spectroscopy

When light sources pass through the diffraction grating then light splits into different wavelengths. The light source produces two types of patterns that are shown as destructive and non-destructive. The light source is in the form of quanta that is quantitation.

Question

1. NAOME,
a.
TsO
OTs
H3C
2. КОН
3. Нао", д
1. LDA
2. NBS
b.
H3C.
*CH3
ČH3
с.
H3C,
H*, Br2
`CH3
CH3
d.
H3C.
`CH3
D30*
ČH3
D..
е.
1. LDA
2. NCS
H3CT CH3
ČH3
f.
1. Mel
„CH3
2. D30*

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