1. Light of wavelength falls normally on a slit of width Calculate the angular position of the first two minima on either side of the principal maximum.
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A: λ= 500 nm=5×10-7 md=5 mm=5×10-3 m And θ=1.22λd
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A: Angular width of principal maxima, θ=λahere, λ=wavelength a = slit width
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Q: n. Find the minimum number of lines needed in a dit
A: 2895
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- Light of wavelength generally falls on a slit of width. Determine the angular location of the first two minima on each side of the main maximum.A diffraction grating is 2.10 cm wide and contains 2100 lines, When used with light of a certain wavelength, a third-order maximum is formed at an angle of 22.0°. What is the wavelength (in nm)? Number UnitsExercise 35.16 Coherent light of frequency 6.38x1014 Hz passes through two thin slits and falls on a screen 84.0 cm away. You observe that the third bright fringe occurs at + 3.12 cm on either side of the central bright fringe.
- Needs Complete typed solution with 100 % accuracy.Don't use chat gpt It Chatgpt means downvoteProblem 4 | The full width at half maximum (FWHM) of the central diffraction maximum is defined as the angle between the two points in the pattern where the intensity is one-half that at the center of the pattern. (a) Show that the intensity drops to one-half of the maximum value when sin² a = a²/2. (b) Verify that a = 1.39 radians (about 80°) is a solution to the transcendental equation of part (a). (c) Show that the FWHM is A0 = 2 sin ¹ (0.443\/a). (d) Calculate the FWHM of the central maximum for slits whose widths are 1.0, 5.0, and 10 wavelengths.