1. Let f:Z - Z, defined by f(2) = 2 (mod n), V z E Z, then kerf is (B) nz (A) (0) (C) Z (D) (0,1)

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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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1. Let f:Z - Z, defined by f(2) = 2 (mod n), V z EZ, then kerf is
(B) nz
2. S=le,a,a".b,ab,a'b: a-b'=(ab}*=e), centralizer of of X=le,a,a') in S, is
(B) (e)
(A) (0)
(C) Z
(D) (0,1)
(A) (e, a)
(C) (e,b)
(D) (e,a,a)
3. De-(e,r,r,r's,rs,r's,r's: r=s=frs}"=e}, then Normalizer of X-le,r,r.r'l is
(A) (e,s)
(8) (e,r')
(C) (e,r,rr"}
(미 D.
Transcribed Image Text:1. Let f:Z - Z, defined by f(2) = 2 (mod n), V z EZ, then kerf is (B) nz 2. S=le,a,a".b,ab,a'b: a-b'=(ab}*=e), centralizer of of X=le,a,a') in S, is (B) (e) (A) (0) (C) Z (D) (0,1) (A) (e, a) (C) (e,b) (D) (e,a,a) 3. De-(e,r,r,r's,rs,r's,r's: r=s=frs}"=e}, then Normalizer of X-le,r,r.r'l is (A) (e,s) (8) (e,r') (C) (e,r,rr"} (미 D.
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