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(a) Calculate the electric field E, due to Q₁ at x = 3 cm. E₁: N/C (b) Calculate the electric field E₂ due to Q₂ at x = 3 cm. E₂: N/C (c) Calculate the net electric field at x = 3 cm due to Q₁ and Q₂. Enet ✔N/C

(a) Calculate the electric field E, due to Q₁ at x = 3 cm. E₁: N/C (b) Calculate the electric field E₂ due to Q₂ at x = 3 cm. E₂: N/C (c) Calculate the net electric field at x = 3 cm due to Q₁ and Q₂. Enet ✔N/C

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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1. In the figure below, Q₁ (-6 µC) by Q₂ (2 µC) are shown. Use k =9x10⁹ Nm²/C². Q1 x=0 x-3cm x 4cm X Using Part 1, the electric field due to Q₁ and Q₂ at x = 3 cm should have looked like this. Q₂ is closer to the point x=3 cm compared to Q₁. Therefore, |E₂| > |E₁|. Both fields point in the negative x- direction. E₁ E₂ x=3cm (a) Calculate the electric field E, due to Q₁ at x = 3 cm. 1 E₁: ✔N/C (b) Calculate the electric field E₂ due to Q₂ at x = 3 cm. E₂: |N/C (c) Calculate the net electric field at x = 3 cm due to Q₁ and Q₂. N/C E net
Transcribed Image Text:1. In the figure below, Q₁ (-6 µC) by Q₂ (2 µC) are shown. Use k =9x10⁹ Nm²/C². Q1 x=0 x-3cm x 4cm X Using Part 1, the electric field due to Q₁ and Q₂ at x = 3 cm should have looked like this. Q₂ is closer to the point x=3 cm compared to Q₁. Therefore, |E₂| > |E₁|. Both fields point in the negative x- direction. E₁ E₂ x=3cm (a) Calculate the electric field E, due to Q₁ at x = 3 cm. 1 E₁: ✔N/C (b) Calculate the electric field E₂ due to Q₂ at x = 3 cm. E₂: |N/C (c) Calculate the net electric field at x = 3 cm due to Q₁ and Q₂. N/C E net
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1. In the figure below, Q₁ (-6 μC) by Q₂ (2 μC) are shown. Use k=9x10° Nm²/C². Q1 x=0 Q2 x=3cm x 4cm Using Part 1, the electric field due to Q₁ and Q₂ at x = 3 cm should have looked like this. Q₂ is closer to the point x=3 cm compared to Q₁. Therefore, |E₂| > |E₁|. Both fields point in the negative x- direction. EL E₂ x 3cm (a) Calculate the electric field E, due to Q₁ at x = 3 cm. E₁: 60x10 N/C (b) Calculate the electric field E₂ due to Q₂ at x = 3 cm. E₂: 180x10N/C (c) Calculate the net electric field at x = 3 cm due to Q₁ and Q₂. Enet 240x10N/C ! No, that's not the correct answer.
Transcribed Image Text:1. In the figure below, Q₁ (-6 μC) by Q₂ (2 μC) are shown. Use k=9x10° Nm²/C². Q1 x=0 Q2 x=3cm x 4cm Using Part 1, the electric field due to Q₁ and Q₂ at x = 3 cm should have looked like this. Q₂ is closer to the point x=3 cm compared to Q₁. Therefore, |E₂| > |E₁|. Both fields point in the negative x- direction. EL E₂ x 3cm (a) Calculate the electric field E, due to Q₁ at x = 3 cm. E₁: 60x10 N/C (b) Calculate the electric field E₂ due to Q₂ at x = 3 cm. E₂: 180x10N/C (c) Calculate the net electric field at x = 3 cm due to Q₁ and Q₂. Enet 240x10N/C ! No, that's not the correct answer.
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