1. In the circuit of Figure 1, if Vab = 220 230°, Vpc = 220 2 – 90°, Vca = 220- 150° V, %3D find the line currents. 10+ j20 L 10 - j12 Q ab 10+ j2 Q I 10 – j12 Q! 10 - j12 2 10+j2 Ω L. Figure 1

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Q: Figure n V/0⁰ 0.2 0 ww + a 0.3 0 m 12.4 V/120° ¹₂ mmom 1.60 0.80 V-120° 0.4 Ω b с j3.4ΩΑ j5.6 MB…

A: A three-phase source with peak value Vm=300 V supplies power to a star-connected three-phase load.

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A: To find the power factor of current source in the given circuit

Q: Find the unknown currents in figure below Assume X -20 A Y=19 A Z -16 A. YA 5A I: + ZA XA 3A3 In

A: The given circuit is, X=20 AY=19 AZ=16 A

Q: VZ-240, FIND: Vbn van Van=300/30 VZO Vab VZ-120 b a 2+j3 faz B LAB 2 IBC Z ICA Z 10-js C

A: it is asked to find Vbn, Vcn, Vab for given 3 phase system

Q: 10 10 <0°v IB/ dooo پیشر J5 Ic 10 < 30° v HI. j4 rooo -58. IE 5 5<0°v

A: Simplified Circuit :

Q: 2. Solve I using Nodal analysis 5/0° A 2Ω j1Q 20/-90° V (+ -j2 Q 21 4Ω

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Q: Obtain the magnitude of the current l, in Figure. express answer in amperes 5Ω 40/90° V τ 8Ω -j2Ω…

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Q: The total impedance of the circuit iz Lw Żtotal = R+ Žequiv = R – j- %3D w2 LC – 1

A: Z⏞total=R+Z⏞equivZ⏞total=R-jLωω2LC-1

Q: VZ-240 FIND? Van=300/30 VZ0 VZ-120 JAB IBC ICA b с 2+j3 J₁A B IAB 2 IBC Z ICA N 10-js C

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A: In the  given circuit                             , VGs  (Th)  = 4  vVGs (en)   = 7vID   = 7 mA (a…

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Q: 5A rms /60Hz L1 100mH L2 www. 150mH C1 = 2.2μF 2 + 10V rms 60Hz + R1 V 1kQ 1

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A: Given data: iT=2+1.5sin1000t+1cos3000t-0.5sin4000t A

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Q: A non-sinusoidal current source (iT=2+1.5sin1000t+ 1cos300Ot-0.5sin4000t) A is applied to the…

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Q: VZ-240 C FIND: Vbn Van a Van=300/30 VZ0 Vab Voc Vca VZ-120 + b JAB IBC ICA a b 2+j3 La A I6B IcC IaA…

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Q: A non-sinusoidal current source (iT=2+1.5sin1000t+ 1cos3000t- 0.5sin4000t) A is applied to the…

A: Given iT=2+1.5sin100t+1cos3000t-0.5sin4000t A

Q: Question 3) In the above circuit VL-326 and ZL = 26 + j41, find the "Ib" line and "IAB" phase…

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Q: 1. Use Kirchhoff's Laws to find the branch currents indicated in the following networks: 2420°v I1…

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Q: Use only KIRCHHOFF'S LAWS to find the branch currents. Thank you!

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Q: The value of the current , in Figure 2 is; 5/0° A j8 2 -j22 Figure 2 (A) -1.67 B 220° 6.67 4290° eee

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