1. In some chickens, the gene for feather color is controlled by codominance. The allele for black is B and theallele for white is W. The heterozygous phenotype is known as erminette (black and white spotted). If 2erminette chickens are crossed, what is the probability that:They would have a black chick?They would have a white chick?%2. Human blood types are determined by genes that follow the CODMINANCE pattern of inheritance. There are2 dominant alleles (IA and IB) and one recessive allele (i).Blood Type (Phenotype)GenotypeCan donate blood to:Can receive blood from:iiA,B,AB and OA,B,AB,O (universalreceiver)АВJA|BABJAJA or 1AiАВ, АO,AАВ, ВO,B!al JO glala) Pretend the Brad Pitt is homozygous for the type B allele and Angelina Jolie is type "O". What are all thepossible blood types for the baby?b) Draw a Punnett square showing all the possible blood types for the offspring produced by type "O" motherand a type "AB" father PART 6: CODOMINANCE (1 POINT)There is another pattern of inheritance that also is an example of lack of dominance. In this situation, if theresulting phenotype exhibits both traits of the parents, the offspring phenotype is said to be the result ofcodominance. Examples of this include A and B blood types in humans, sickle-cell disease, and coat color incattle and horses.In this last example, cattle which are homozygous for a red coat allele are red, cattle which are homozygous for awhite coat allele are white, and heterozygous cattle appear roan (red hairs mixed with white) due to codominanceof the red and white coat color alleles, In this case it is common to use two different capital letters of the alphabetas superscripts to a common letter, to represent the red and white coat color alleles. For example, red cattfewould be C"c white cattle would be C"C" and roan cattle would be C"C", where:red coatCW = white coatandHow is this different from red, white, and pink flowers?Cattle coat color would be considered incompletely dominant if C"C" were completely pink, instead of a patchyred and white.Camation petal color would be considered codominant if RW were red and white striped, instead of solid pink.Nevertheless, both these patterns of inheritance are important for they deviate from the basicdominant/recessive pattern of inheritance.In summary:Cattle and Horse Coat ColorResulting PhenotypeGenotypec*CRC"CWC*CWRed coatWhite coatRoan coat (red hairs mixed with white)PRACTICE PROBLEM:A roan bull (male) is mated with a white cow (female). What are the possible offspring?Cow's genotype:Bull's genotype:Fill in the Punnett square and give the phenotypepercentages of this cross:Punnett square:color% arecolor% areCould Red offspring be born to a White cow mated with a Roan bull?

Gene is the specific sequence of nucleotides which encode a polypeptide.

1. In some chickens, the gene for feather color is controlled by codominance. The allele for black is B and the allele for white is W. The heterozygous phenotype is known as erminette (black and white spotted). If 2 erminette chickens are crossed, what is the probability that: They would have a black chick? They would have a white chick? 2. Human blood types are determined by genes that follow the CODMINANCE pattern of inheritance. There are 2 dominant alleles (IA and IB) and one recessive allele (i). Blood Type (Phenotype) Genotype Can donate blood to: Can receive blood from: ii A,B,AB and O A,B,AB,O (universal receiver) АВ JAIB AB JAJA or 1Ai АВ, А O,A IB|B or 1Bi АВ, В O.B a) Pretend the Brad Pitt is homozygous for the type B allele and Angelina Jolie is type "O". What are all the possible blood types for the baby? b) Draw a Punnett square showing all the possible blood types for the offspring produced by type "O" mother and a type "AB" father

1. In some chickens, the gene for feather color is controlled by codominance. The allele for black is B and the allele for white is W. The heterozygous phenotype is known as erminette (black and white spotted). If 2 erminette chickens are crossed, what is the probability that: They would have a black chick? They would have a white chick? 2. Human blood types are determined by genes that follow the CODMINANCE pattern of inheritance. There are 2 dominant alleles (IA and IB) and one recessive allele (i). Blood Type (Phenotype) Genotype Can donate blood to: Can receive blood from: ii A,B,AB and O A,B,AB,O (universal receiver) АВ JAIB AB JAJA or 1Ai АВ, А O,A IB|B or 1Bi АВ, В O.B a) Pretend the Brad Pitt is homozygous for the type B allele and Angelina Jolie is type "O". What are all the possible blood types for the baby? b) Draw a Punnett square showing all the possible blood types for the offspring produced by type "O" mother and a type "AB" father

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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3. In fruit flies, red eyes (R) are dominant over purple eyes (r). Two red-eyed fruit flies were crossed, producing the following offspring: 76 red-eyed flies 24 purple-eyed flies a. What is the approximate ratio of red-eyed to purple-eyed flies? . b. Based on your experience with previous problems, what two genotypes give rise to this ratio?. c. What are the parents' genotypes?. d. What is the genotypic ratio of the F; offspring?. e. What is the phenotypic ratio of the F, offspring?
2. A person with a curly hair mates with a person having a straight hair. All their offspring have wavy hair (indicating incomplete dominance). What would be the result of a cross between two wavy haired individuals? Give the genotypic and phenotypic ratio.
1. A pure line Brown coat goat is crossed with pure line White coat goat. Consider the Brown coat is dominant over white coat. a. What is the result (F1) of this cross? b. What is the result when 2 F1 hybrid from (a) is crossed? Give the phenotype, genotype and their ratio. Make sure the phenotype and genotype were aligned with its ratio.
8. Construct a Punnett square for a cross between a heterozygous black guinea pig and a homozygous white guinea pig. a. What genotypes would you expect in the offspring? b. What percentage or ratio of each genotype would you expect in the offspring? C. What phenotypes would you expect in the offspring?
4.
2. Brown eyes are dominant over blue eyes in humans. Having a peaked hairline is dominant over having a smooth hairline in humans. Two such humans decide to have offspring – who will also be human, because you know – genes. One of the parents has blue eyes and is heterozygous for a peaked hairline. The other parent is brown-eyed with a peaked hairline but is heterozygous for both traits. a) Complete a Punnett square showing all possible genotypes of their offspring. b) What is the probability of this couple producing a child with blue eyes? c) What is the probability of producing a child who has both brown eyes and a smooth hairline?
3. If two gene pairs A and a and Band b are assorting independently with A dominant to a and B dominant to b, what is the probability of obtaining: a. an AB gamete from an AaBb individual? b. an AABB zygote from an AaBb x AaBb cross? C. an aaBb offspring from an AABB x aabb cross? d. a phenotype aB from an Aabb x aaBb cross? e. an ab gamete from an aaBB individual?
1. Two loci found in mice are suspected to be linked. To test this hypothesis, a group of graduate students performed a test cross between mice that are true breeding for both dominant traits and mice that are true breeding for both recessive traits. Individuals from the F1 generation were crossed with individuals that express both recessive traits. The phenotypic results are shown in the table below. Use chi-square analysis to determine if the graduate students’ hypothesis is supported by the evidence. Phenotype Number of OffspringDominant 1, Recessive 2 132Dominant 1, Dominant 2 128Recessive 1, Recessive 2 118Recessive 1, Dominant 2 124 a. What are the degrees of freedom and the critical chi-square value (from the table)?b. What is the calculated chi-square value?c. Do the results support that the loci are linked or that they are independently assorted (unlinked)?
4. Mr. Salazar has Type A blood while Mrs. Salazar has Type B. They have four children. Bobbie has Type A, Gabbie has Type B, Alex has Type AB, and Teddie has Type O. What are the genotypes of all six people in this family? NOTE: The ABO blood type gene has three alleles. IA and IB are codominant; i (for Type O) is recessive to both.
2. A trait in garden peas involves the curling of leaves. A dihybrid cross was made involving a plant with yellow pods and curling leaves to a wild-type plant with green pods and normal leaves. All F1 offspring had green pods and normal leaves. The F1 plants were then crossed to plants with yellow pods and curling leaves. The following results were obtained: 117 green pods, normal leaves 115 yellow pods, curling leaves 78 green pods, curling leaves 80 yellow pods, normal leaves A. Conduct a chi square analysis to determine if these two genes are linked. B. If they are linked, calculate the map distance between the two genes. How accurate do you think this distance is?
7. Instead of one big square it is much easier to make two small Punnett squares, one for each gene. In the space at the bottom of page, draw the two squares (from 4d and 5b on previous page). Indicate the phenotypic ratios for each square and then multiply to get the combined probabilities. For example, the probability of having both diseases requires multiplying the probability of each event. a. Is the inheritance of an "A" or "a" allele dependent on (or affected by) the inheritance of a "B" or b" allele? Why or why not? (hint: Which of Mendel's Laws is involved?) b. What is the chance that their child will be phenotypically normal (for both genes)? Show your work: c. What is the chance that their child will be genotype aabb (affected with both diseases)? Show your work: d. What is the chance that they will have a boy who has genotype AaBb (carrier for both diseases like his parents)? Show your work:
2. In terms of pea plant height, tall plants (T) are dominant over dwarf plants (t). Purple flowers (P) are dominant over white flowers (p). Create a Punnett square that shows all of the possible offspring that could occur from breeding the following: a.) Plant 1: Heterozygous dominant for plant height, homozygous dominant for flower color b.) Plant 2: Heterozygous dominant for plant height, homozygous recessive for flower color c.) Include the percentage/ratio of occurrence for each phenotype.