I really don't understand this question at all. I know its a big ask, but could you please go through each part and explain to me why it has an unique solution, no solution or multiple solutions. I know it says no justification required but I think I need one to understand the question. 1. In cach case decide if the linear system of equations has a unique solution, no solutionor many solutions. No justification is required.3x1 +(i)3,+ 212 =-1.I3 = 0,I2 + I3 = 0,(ii)211I3 = 0.I2 - I3 =1,(iii)I2 + 135,211I210.%3D+ 2r2+ 3r2 + 4r3 + I4+ 6x2 + 8rs + 46r3 + r40.(iv)0.%3D0.+ 2r23r2 + Ary + r46r3 + r4 = 3,2.(v)%3D1.I3 + ri=D0.linear comations

Answered: Image /qna-images/answer/ffaed5c0-dc23-43ab-989a-231b54bf4324.jpg

1. In cach case decide if the linear system of equations has a unique solution, no solution or many solutions. No justification is required. 311 + 3, (i) I1 + 21, = -1. - I2 - I3 = 0, I2 + I3 = 0, I3 = 0. (ii) 21 -I - I = 1, (iii) I2 + I3%3D 5, 211 - I3 10. %3D -II + 2r2 I + 3r2 + 4r3 + 1A 2 + 6rz + 8r3 + I4 6r3 + I4 = 0, = 0. (iv) = 0. + 2r2 3r + Ars + 4 6r3 + r4 = 3. 2. %3D (v) 1.

1. In cach case decide if the linear system of equations has a unique solution, no solution or many solutions. No justification is required. 311 + 3, (i) I1 + 21, = -1. - I2 - I3 = 0, I2 + I3 = 0, I3 = 0. (ii) 21 -I - I = 1, (iii) I2 + I3%3D 5, 211 - I3 10. %3D -II + 2r2 I + 3r2 + 4r3 + 1A 2 + 6rz + 8r3 + I4 6r3 + I4 = 0, = 0. (iv) = 0. + 2r2 3r + Ars + 4 6r3 + r4 = 3. 2. %3D (v) 1.

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Question

I really don't understand this question at all. I know its a big ask, but could you please go through each part and explain to me why it has an unique solution, no solution or multiple solutions. I know it says no justification required but I think I need one to understand the question.

1. In cach case decide if the linear system of equations has a unique solution, no solution
or many solutions. No justification is required.
3x1 +
(i)
3,
+ 212 =
-1.
I3 = 0,
I2 + I3 = 0,
(ii)
211
I3 = 0.
I2 - I3 =
1,
(iii)
I2 + 13
5,
211
I2
10.
%3D
+ 2r2
+ 3r2 + 4r3 + I4
+ 6x2 + 8rs + 4
6r3 + r4
0.
(iv)
0.
%3D
0.
+ 2r2
3r2 + Ary + r4
6r3 + r4 = 3,
2.
(v)
%3D
1.
I3 + ri
=D0.
linear comations

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